<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
Answer:
a) 0.0002
b) 0.0057
c) 0.0364
Step-by-step explanation:
Lets start by stating the probabilities of a person belonging to each policy:
Standard: 0.3
Preferred: 0.5
Ultra- Preferred: 0.2
The probability of person belonging to each policy AND dying in the next year:
Standard: 0.3 x 0.015 = 0.0045
Preferred: 0.5 x 0.002 = 0.001
Ultra- Preferred: 0.2 x 0.001 = 0.0002
a) The probability a ultra - preferred policy holder dies in the next year is 0.001. To find the probability of a person being both a ultra - preferred policy holder AND die in the next year is: 0.001 x 0.2= 0.0002
b) The probability is given by adding the probabilities calculated before :
0.0045 + 0.001 + 0.0002 = 0.0057
c) We use the results above again. This is 0.0002 / (0.001 + 0.0045). The answer comes out to be 0.0364
Answer: 1 1/3 packs of treats
Step-by-step explanation:
2 1/9 + 5/9 = 2 6/9, which can be simplified to 2 2/3.
We subtract 2 2/3 from 4, giving us 1 1/3
Answer:
B
Step-by-step explanation:
The m to the y can’t equal to m so it’s b
