Answer:
![A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-6%5C%5C8%265%5C%5C19%26-10%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
![A =\left[\begin{array}{cc}2&-2\\3&4\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%264%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
![B = \left[\begin{array}{cc}4&-1\\-1&2\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-1%5C%5C-1%262%5Cend%7Barray%7D%5Cright%5D)
Required

To do this, we simply multiply the rows of A by the column of B;
So, we have:
![A * B = \left[\begin{array}{ccc}2*4 + -2*-1&2*-1+-2*2\\3*4+4*-1&3*-1+4*2\\4*4-3*-1&4*-1-3*2\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2A4%20%2B%20-2%2A-1%262%2A-1%2B-2%2A2%5C%5C3%2A4%2B4%2A-1%263%2A-1%2B4%2A2%5C%5C4%2A4-3%2A-1%264%2A-1-3%2A2%5Cend%7Barray%7D%5Cright%5D)
![A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-6%5C%5C8%265%5C%5C19%26-10%5Cend%7Barray%7D%5Cright%5D)
Answer:
LA = 120 sq cm
SA = 132 sq. cm.
Step-by-step explanation:
LA = ph where p = perimeter of the base and h = the height of prism.
Your base is a triangle. The third side =
= 
Now, the perimeter of the triangle is 3 + 4 + 5 = 12
So, LA = 12(10) = 120 sq cm
The area of the base is the area of a triangle. A = bh/2 = 4(3)/2 = 6
SA = 2B + LA where B is the area of the base
SA = 2(6) + 120 = 12 + 120 = 132 sq. cm.
G(x) = 4x^2 + 24x + 30
g(x) = 4(x+3)^2 - 6
answer is <span> B. The graph of f(x) = x^2 is shifted left 3 units.
</span>
hope it helps
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️


Add sides 3x


♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️