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avanturin [10]
3 years ago
9

Examine the equation.

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

10x + 18

You cancel out the lowest variable term to only have one variable term.

Step-by-step explanation:

-3x+3 then do 7x+3

10x + 18

You cancel out the lowest variable term to only have one variable term.

Tell me if it works.

Hope it helped.

Sedbober [7]3 years ago
5 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

- 3x + 18 = 7x

7x =  - 3x + 18

Add sides 3x

+ 3x + 7x =  + 3x - 3x + 18

10x = 18

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Step-by-step explanation:

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Write L if it is likely to happen and U if unlikely to happen.
maria [59]

Answer:

Probabilities

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a.      4/5                                 5/8

b.     3/5                                  3/8

c.     4/5                                  4/7

d.    0.3                                  0.09

e.    5/6 and 4/5                   2/3

Step-by-step explanation:

Probabilities in Percentages:

a. The probability of 4/5 = 80% and 5/8 = 62.5%

b. The probability of 3/8 = 37.5% and 3/5 = 60%

c. The probability of 4/5 = 80% and 4/7 = 57%

d. The probability of 0.3 = 30% and 0.09 = 9%

e. The probability of 2/3 = 67% and 4/5 = 80% and 5/6 = 83%

b) To determine the relative values of the fractional probabilities, it is best to reduce them to their fractional or percentage terms.  When this is done, the relative sizes become obvious, and then, comparisons can be made.

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Step-by-step explanation:


6 0
4 years ago
Read 2 more answers
Which expression is equivalent to sqrt8x^7y^8? assume x&gt;0
Ilia_Sergeevich [38]

Answer:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

Step-by-step explanation:

Given

\sqrt{8x^7y^8

Required

Evaluate

\sqrt{8x^7y^8

Separate each factor with multiplication sign

\sqrt{8*x^7*y^8

Express 8 as 4 * 2 and x^7 as x^6 * x

\sqrt{4 * 2 *x^6 * x*y^8

Split each factor

\sqrt{4} * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Evaluate \sqrt4

2 * \sqrt{2} *\sqrt{x^6} * \sqrt{x}*\sqrt{y^8}

Apply law of indices:

2 * \sqrt{2} * x^{6*\frac{1}{2}} * \sqrt{x} * y^{8*\frac{1}{2}}

2 * \sqrt{2} * x^3 * \sqrt{x} * y^4

Reorder

2* x^3 * y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2}  * \sqrt{x}

2x^3y^4 * \sqrt{2*x}

2x^3y^4 * \sqrt{2x}

2x^3y^4 \sqrt {2x

Hence:

\sqrt{8x^7y^8= 2x^3y^4 * \sqrt{2x}

8 0
3 years ago
Read 2 more answers
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