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Bogdan [553]
3 years ago
11

Help no time plzzzz plz plz​

Mathematics
1 answer:
Sav [38]3 years ago
8 0

Answer:

FALSE

Step-by-step explanation:

<E in ∆AED ≅ <E in ∆CEB.

Both are 90°.

Side ED ≅ Side EB

Side AD ≅ Side CB.

Thus, two sides (ED and AD) and a non-included angle (<E) of ∆AED are congruent to corresponding two sides (EB and CB) and a non-included angle (<E) of ∆CEB. Therefore, by A-S-S Congruence Theorem, both triangles are congruent to each other not by SSS.

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Sarawong had some candy to give to his four children. He first took nine pieces for himself and then evenly divided the rest amo
svet-max [94.6K]
9+3+3+3=21 or you could do 4*3+9

5 0
3 years ago
Read 2 more answers
What is the inverse of the function f(x) = 4x + 8?
morpeh [17]

Answer:

(A) h(x) = 1/4x -2

Step-by-step explanation:

Given: f(x)=4x+8

Rewrite with y: y=4x+8

Switch x and y: x=4y+8

Solve for y: x-8=4y

(x-8)/4=y

1/4x-2=y

y=1/4x-2

This means that h(x) = 1/4x -2 is the correct answer

8 0
3 years ago
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sveta [45]
The answer would be “-876”
6 0
3 years ago
Gerry wants to construct a triangle with segments that
alexira [117]

Answer:

See Explanation

Step-by-step explanation:

Sample Response: No, the triangle is not possible. The triangle inequality rule states the sum of any two sides must be greater than the third side. 6 + 4 is 10, which is less than 11.

5 0
3 years ago
A- CE=CD <br> B- CE = CA <br> C- BF=DF <br> D- DF=EF<br><br> please help!!
Oksana_A [137]

The perpendicular bisector theorem gives the statements that ensures

that \overleftrightarrow{FG} and \overleftrightarrow{AB} are perpendicular.

The two statements if true that guarantee  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB} are;

  • \overline{CE} = \overline{CD}
  • \overline{DF} = \overline{EF}

Reasons:

The given diagram is the construction of the line \mathbf{\overleftrightarrow{FG}} perpendicular to line \mathbf{\overleftrightarrow{AB}}.

Required:

The two statements that guarantee that  \overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}.

Solution:

From the point <em>C</em> arcs <em>E</em> and <em>D</em> are drawn to cross line \overleftrightarrow{AB}, therefore;

\overline{CE} = \mathbf{\overline{CD}} arcs drawn from the same radius.

\overleftrightarrow{FG} is perpendicular to line \overleftrightarrow{AB}, given.

Therefore;

\overline{DF} = \overline{EF}  by perpendicular bisector theorem.

Learn more about the perpendicular bisector theorem here:

brainly.com/question/11357763

7 0
3 years ago
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