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3 years ago

The answer to the problem plz

Mathematics

1 answer:

Vlad1618 [11]3 years ago

4 0

B I think hope you do good

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Marivel paid $16.64 for 3 pounds of almonds. What is the price for 15 pounds of almonds?

finlep [7]

Answer:

$ 83.2

Step-by-step explanation:

3 pounds = 16.64

15 pounds = ?

15 pounds = 5 × 16.64

= $ 83.2

6 0

3 years ago

Please Help!!!!!!! No stupid answers

Snowcat [4.5K]

A. The ratio of the person's shadow to their height is 6:2 or 3:1, so the height of the shadow is 360/3 or 120 m.
B. The model car's length divided by the ratio to the real car, which is 8.5/0.8 = 10.625 cm long.

6 0

3 years ago

Read 2 more answers

Write and then evaluate an expression for the following number line

drek231 [11]

Answer:

ok there are know boxes

Step-by-step explanation:

6 0

3 years ago

If x and y are two supplementary angles whereas m

Rudiy27

Answer:

110degrees

Step-by-step explanation:

Complete question

Q4: If x and y are two supplementary angles whereas m<x=70 then find the m<y.

The sum of two supplementary angles is 180degrees, hence;

m<x + m<y = 180

70 + m<y = 180

m<y = 180 - 70

m<y = 110degrees

Hence the measure of ,=m<y is 110degrees

5 0

3 years ago

The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 oun

Ugo [173]

Answer: A) .1587

Step-by-step explanation:

Given : The amount of soda a dispensing machine pours into a 12-ounce can of soda follows a normal distribution with a mean of 12.30 ounces and a standard deviation of 0.20 ounce.

i.e. $\mu=12.30$ and $\sigma=0.20$

Let x denotes the amount of soda in any can.

Every can that has more than 12.50 ounces of soda poured into it must go through a special cleaning process before it can be sold.

Then, the probability that a randomly selected can will need to go through the mentioned process = probability that a randomly selected can has more than 12.50 ounces of soda poured into it =

$P(x>12.50)=1-P(x\leq12.50)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{12.50-12.30}{0.20})\\\\=1-P(z\leq1)\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\=1-0.8413\ \ \ [\text{By z-table}]\\\\=0.1587$

Hence, the required probability= A) 0.1587

6 0

3 years ago