The answer to the problem plz

Ryan made a $3000 down payment on a car. the total cost of the car was $7500. He made 36 equal monthly payments to pay the car i

yawa3891 [41]

The car costs $7500
7500-3000=4500 to be paid in monthly payments
4500/36=125
Ryan paid 125 per month

7 0

3 years ago

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During optimal conditions, the rate of change of the population of a certain organism is proportional to the population at time

Lana71 [14]

Answer:

The population is of 500 after 10.22 hours.

Step-by-step explanation:

The rate of change of the population of a certain organism is proportional to the population at time t, in hours.

This means that the population can be modeled by the following differential equation:

$\frac{dP}{dt} = Pr$

In which r is the growth rate.

Solving by separation of variables, then integrating both sides, we have that:

$\frac{dP}{P} = r dt$

$\int \frac{dP}{P} = \int r dt$

$\ln{P} = rt + K$

Applying the exponential to both sides:

$P(t) = Ke^{rt}$

In which K is the initial population.

At time t = 0 hours, the population is 300.

This means that K = 300. So

$P(t) = 300e^{rt}$

At time t = 24 hours, the population is 1000.

This means that P(24) = 1000. We use this to find the growth rate. So

$P(t) = 300e^{rt}$

$1000 = 300e^{24r}$

$e^{24r} = \frac{1000}{300}$

$e^{24r} = \frac{10}{3}$

$\ln{e^{24r}} = \ln{\frac{10}{3}}$

$24r = \ln{\frac{10}{3}}$

$r = \frac{\ln{\frac{10}{3}}}{24}$

$r = 0.05$

So

$P(t) = 300e^{0.05t}$

At what time t is the population 500?

This is t for which P(t) = 500. So

$P(t) = 300e^{0.05t}$

$500 = 300e^{0.05t}$

$e^{0.05t} = \frac{500}{300}$

$e^{0.05t} = \frac{5}{3}$

$\ln{e^{0.05t}} = \ln{\frac{5}{3}}$

$0.05t = \ln{\frac{5}{3}}$

$t = \frac{\ln{\frac{5}{3}}}{0.05}$

$t = 10.22$

The population is of 500 after 10.22 hours.

7 0

2 years ago

At a canning facility, a technician is testing a machine that is supposed to deliver 250 milliliters of product. The technician

Serhud [2]

Answer:

The value of the test statistic is $t = 1.97$

Step-by-step explanation:

The null hypothesis is:

$H_{0} = 250$

The alternate hypotesis is:

$H_{1} \neq 250$

Our test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the null hypothesis value, $\sigma$ is the standard deviation and n is the size of the sample.

In this problem:

$X = 251.6, \mu = 250, \sigma = 5.4, n = 44$

So

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{251.6 - 250}{\frac{5.4}{\sqrt{44}}}$

$t = 1.97$

The value of the test statistic is $t = 1.97$

4 0

3 years ago

What is the value of y in the equation 4(5y –8 –2) = 185 –15?

Rina8888 [55]

In an equation the Left hand side must equal the right hand side 4(5y-8-2)=185-15 20y-32-8=170 20y=170+32+8 20y=210 Therefore y=10,5 When you substitute the 10,5 and solve it on the left and side it's equal to 170 which is the answer on the right hand side

8 0

2 years ago

A line passes through (–1, 5) and (1, 3). Which is the equation of the line?

fredd [130]

Answer:

Use the slope formula and slope-intercept form y = m x + b to find the equation. y = − x + 4

7 0

3 years ago