The answer is
AB = 6.
External value x (external value + internal value) =
External value x (external value + internal value) of the other side
Substitute, transpose, and simplify.
TA x (TA + AB) = TC x (TC + CD)
10 x (10 + (x + 2)) = 8 x (8 + 12)
120 + 10x = 160
10x = 40
x = 4
To find AB: x + 12; x = 4
AB = x + 2
AB = 4 + 2
AB = 6
Answer:
Step-by-step explanation:
Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex 
in the expression:
we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter 
:
So, now we can write the full expression for the parabola:
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
So it work like this
180-72= 108
x+4=108
x=108-4
x=104
Answer:
Step-by-step explanation:
using the rule of exponents
= 
note that 6 = 
, then
= 
=
