The circumference of the vase is 18.84 inches.
<u>Step-by-step explanation:</u>
The circumference of the cylinder is same as the circumference of its base.
Moreover, the base of the cylinder is actually a circle.
So we need to find the circumference of the circle to find the circumference of the cylinder.
From the given figure, we know that the diameter of the base d= 6 inches.
∴The formula for the circumference of the circle = 2πr or dπ.
⇒ circumference = 6×3.14.
= 18.84.
So the circumference of the circle is 18.84 inches.
∴The circumference of the cylindrical vase is also 18.84 inches.
Answer:
2. ![\left[\begin{array}{ccc}1&4\\0&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%264%5C%5C0%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
3. ![\left[\begin{array}{ccc}-3&21&60\\-15&9&-45\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%2621%2660%5C%5C-15%269%26-45%5C%5C%5Cend%7Barray%7D%5Cright%5D)
4. ![\left[\begin{array}{ccc}6&-14\\-2&-6\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%26-14%5C%5C-2%26-6%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
2. This matrix is easy, as it just requires addition.
+ ![\left[\begin{array}{ccc}0&0\\0&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%260%5C%5C0%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
3. This matrix requires for the matrices to be multiplied first, then added.
![\left[\begin{array}{ccc}9&-15&18\\-27&15&-9\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-15%2618%5C%5C-27%2615%26-9%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}-12&36&42 \\12& -6 & -36 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-12%2636%2642%20%5C%5C12%26%20-6%20%26%20-36%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
4. Here we can add the last 2 matrices to find x.
![\left[\begin{array}{ccc}2&-8\\-4&2\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%26-8%5C%5C-4%262%5C%5C%5Cend%7Barray%7D%5Cright%5D)
+ ![\left[\begin{array}{ccc}4&-6\\2&-8 \\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-6%5C%5C2%26-8%20%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
Hope this helps! (Please consider giving brainliest)
For the first question, all you need to know is that the (amount you want) divided by (the amount of cards total) is the probability of getting the amount you want at random. for example, if there are 3 red marbles in a bag of ten marbles, you divide 3 by 10 (0.30) the probability of picking up a red marble is 30%. try adding up how many cards you want to pick up by the number of cards total.
Answer:
that box means the angle is 90 degrees.
Step-by-step explanation:
if you need anymore help just message me
