To elaborate:
To do this problem, we assume that Mr. Sanchez is driving at a constant rate.
According to this information, he has driven 120 mi in 3 hr. To find how much he drives in 5 hr, we first have to find how many mi he drives in 1 hour. To do this, we divide 120 miles by 3 hours, since we assume that he managed to drive an equal amount in each hour.
120/3=40
Therefore Mr. Sanchez drove at a rate of 40 mph.
However, this isn't the final answer. 40 miles is the distance for one hour of driving. To find the distance for 5 hours, we have to multiply the distance by 5 as well.
40 times 5=200
In conclusion, Mr. Sanchez will drive 200 miles in 5 hours.
It is definitely J yes it is
1. 8c^2-26c+15= (4c-3) (2c-5). Break the expression into groups: =(8c^2-6c)+(-20c+15). Factor out 8c^2-6c: 2c(4c-3). Factor out -5 from -20c+ 15: -5(4c-3). Lastly factor out common term (4c-3) and thats how you'll get your answer (4c-3) (2c-5).
2. common factors for 270 and 360 is 90.To find this write the factors of each and find the largest one.270: 1, 270, 2, 135, 3, 90, 5, 54, 6, 45, 9, 30, 10, 27, 15, 18360: 1, 360, 2, 180, 3, 120, 4, 90, 5, 72, 6, 60, 8, 45, 9, 40, 10, 36, 12, 30, 15, 24, 18, 20
3. The factors for 8 a3b2 and 12 ab4 is 4. because 8: 1, 2, 4, 812: 1, 2, 3, 4, 6, 12.
4. 81a^2+36a+4= (9a+2)^2. Break down the expression into groups: (81a^2+18a)+(18a+4). Factor out 9a from 81a^2 +18a: 9a(9a+2). Factor out 2 from 18a+4: 2(9a+2). so the groups you got are now 9a(9a+2)+2(9a+2). Lastley factor out common term (9a+2) to get (9a+2) (9a+2). Finally you get the answer (9a+2)^2.
5. mn-15+3m-5n= (n+3)(m-5). factor out m from nm+3m: m(n+3). Factor out -5 from -5n-15: -5(n+3). And thats how you get the number (n+3)(m-5)
Hope this helped :) Have a great day
Answer:
8 x 10¹³ is your answers hopes it's helpful to you
