Answer:
The amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
Step-by-step explanation:
Given that the Soybean Meal has 46% CP and Oats has 12% CP.
The total amount of ration is 900 lbs of 35% CP.
Let x pounds of Soyabean has been used, so,
the amount of Oats = 900-x lbs.
The CP amount in 900 lbs mixture will be equal to the sum of CP amounts in x lbs Soyabean and 900-x lbs Oats, i.e
35% of 900 = 46% of x + 12% of (900-x)
lbs.
So, the amount of Soyabean = 608.82 pounds.
The amount of Oats = 900-608.82 = 291.18 pounds.
The coordinates would surely be -9,15
Answer:
−3d−5e−2
Step-by-step explanation:
Answer:
40
Step-by-step explanation:
here is a trig calculator
http://www.carbidedepot.com/formulas-trigright.asp
Answer:
<em>F test</em>
Step-by-step explanation:
<em>For any test using the F-distribution, a "F Test" is a capture-all word. In certain circumstances, as individuals speak about the F-Test, it is the F-Test to compare two variances that they actually talk about. </em>
Moreover, in a multitude of tests, the f-statistics is used such as regression analysis, the Chow test and the Scheffe test (a post-hoc ANOVA test).
One should be using Excel, SPSS, Minitab or some other form of software to run the experiment if you are running a F test.
<em><u>Steps include.</u></em>
- State the hypothesis of nullity and the counter hypothesis.
- Determine the value of F. The F value is determined using equation F = (SSE1 – SSE2/m)/SSE2/n-k, where SSE = square residual, m = number of constraints, and k = number of independent variables.
- Find the statistics for F (the critical value for the test). The F statistical formula is: F Statistics = group mean / mean variance of variances within the group.
- The F Statistics can be found in the F-Table.
- The Null Hypothesis is accepted or denied.
