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2 years ago

Salutations young warriors..i have a question needed to be answered

Mathematics

2 answers:

Marrrta [24]2 years ago

8 0

Answer:

I think the answer must be A.

Step-by-step explanation:

$-(7^{-3})(7^{5} )$

=> $-(\frac{1}{7^{3} } )(7^{5} )$

=> $(\frac{-1}{7^{3} } )(7^{5} )$

=> -1 × 7²

=> -7²

=> -49

Hoped this helped.

Anton [14]2 years ago

8 0

Yes the answer is A because 7^-3 multiplied by 7^5 is 49, and since there is a negative by itself, it’s a -49.

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cluponka [151]

Answer:x2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The length of overline CD is 12 units. C^ prime D^ prime is the image of overline CD under a dilation with a scale factor of n.

Rufina [12.5K]

Answer:

A, D , and E

Step-by-step explanation:

We have that:

$\overline{CD} = 12 \: units$

$\overline{C'D'}$

is the image of CD after a dilation of scale factor n.

We use the relation between the image length and object length:

$\overline{C'D'} = n \times \overline{CD}$

Option A

If n=3/2, then

$\overline{C'D'} = \frac{3}{2} \times 12 = 3 \times 6 = 18 \: units$

This is true.

Option B

If n=4, then

$\overline{C'D'} = 4 \times 12 = 36 \: units$

This is false.

Option C

If n=8, then

$\overline{C'D'} = 8 \times 12 = 96 \: units$

This too is false.

Option D

If n=2, then

$\overline{C'D'} = 2 \times 12 = 24 \: units$

This is true

Option E

If n=3/4, then

$\overline{C'D'} = \frac{3}{4} \times 12$

$\overline{C'D'} = 3 \times 3 = 9 \: units$

This is also true.

4 0

3 years ago

Which is the most accurate way to estimate 25% of 53?

Alex Ar [27]

You can calculate them out and check which one is the most accurate

so if one of the choices was 1/3 of 50, then you would do:
1/3 in the calculator (should be 0.333...) times 50

And you can compare it with the EXACT number, which is:
0.25*53=13.25

This way you can test all the options

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3 years ago

Slope for (6,5) (14, -3)

otez555 [7]

Answer:

m= -1

I hope this helped, have a great day!! <3

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2 years ago

Find the exact value of tan A in simplest radical form.

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Answer: