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natali 33 [55]
3 years ago
12

When inviting more than one person to a calendar,

Computers and Technology
1 answer:
Makovka662 [10]3 years ago
8 0
B) Comma. is the answer
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When a JSP page is compiled, what is it turned into?
77julia77 [94]

Answer: Servlet

Explanation: JSP page compilation is the process of compiling of the file before it can be turned towards the live server .There is a request that is made towards the JSP page  then is compiled into a JSP servlet. Before the execution of the JSP program, it is turned in to a JSP servlet .JSP is a program that work on the server side and reduce the work load of the developers.

5 0
3 years ago
1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a s
masya89 [10]

Answer:

import java.util.Scanner;

public class TestClock {

   public static void main(String[] args) {

 Scanner in = new Scanner (System.in);

       System.out.print("Enter favorite color:");

 String word1 = in.next();

       System.out.print("Enter pet's name:");

 String word2 = in.next();

       System.out.print("Enter a number:");

 int num = in.nextInt();

       System.out.println("you entered: "+word1+" "+word2+" "+num);

   }

}

Explanation:

Using Java Programming language

  1. Import the Scanner class
  2. create an object of the scanner class
  3. Prompt user to enter the values for the variables (word1, word2, num)
  4. Use String concatenation in System.out.println to display the output as required by the question.

7 0
3 years ago
Where can I learn how you hack?​
morpeh [17]

Answer:

www.udemy.com

5 0
2 years ago
Read 2 more answers
"As part of integrating your solution your client indicates that they have certain technologies enabled on their network that al
erastovalidia [21]

Answer:

quality of service

Explanation:

6 0
3 years ago
Given that it takes 0.08 ms to travel from one track to the next of a hard drive; that the arm is originally positioned at Track
daser333 [38]

Answer:

Time taken to travel from one track to the next = 0.08ms

Initial track= 15     0

4      (15-4)*(0.08)= 0.88

40     (40-4)*(0.08)= 2.88

35      (40-35)*(0.08)= 0.4

11       (35-11)*(0.08)= 1.92

14       (14-11)*(0.08)= 0.24

7         (14-7)*(0.08)= 0.56

----------------------------------------------

Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms

Explanation:

We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.

4 0
3 years ago
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