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liq [111]
1 year ago
8

When correctly implemented, what is the only cryptosystem known to be unbreakable?

Computers and Technology
1 answer:
Leona [35]1 year ago
6 0

When accurately executed, the only cryptosystem known to be unbreakable is called: "One-time Pad" (Option D)

<h3>What is a Crypto System?</h3>

The one-time pad is a cryptographic approach that cannot be broken but needs the usage of a single-use pre-shared key that is not less than the message being delivered. A plaintext is coupled with a unique secret key in this manner.

It should be emphasized that in cryptography, a cryptosystem is a collection of cryptographic algorithms that are required to perform a certain security function, such as confidentiality. A cryptosystem is often composed of three algorithms: one just for key generation, one for encrypting, and one for deciphering.

Learn more about Crypto System:
brainly.com/question/15084188
#SPJ1

Full Question:

When correctly implemented, what is the only cryptosystem known to be unbreakable?

A) Transposition cipher

B) Substitution cipher

C) Advanced Encryption Standard

D) One-time Pad

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(1)Minterms complement = XYZ (2) Compliment of Minterms = Σm(0,1, 2 , 4 , 6) (3) (X+Y+Z) (4) Minimized SOP = Z + XY

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Explanation:

Solution

Recall that:

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

(1) Canonical Disjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as minterms

In Minterm we assign 'I' to each uncomplimented variable and '0' to each complemented/complementary variable

For the given question stated we ave the following:

Minterms = XYZ, XYZ, XYZ, XYZ, XYZ.

(2) Canonical Conjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as maxterms.

In Maxterms we assign '0' to each uncomplimented variable and '1' to each complemented/complementary variable

Compliment of Minterms = Σm(0,1, 2 , 4 , 6)

Maxterms = πM

Note: Kindly find an attached copy of the complete solution to this question below.

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