Answer:
![Range =1.41-0.66 = 0.75](https://tex.z-dn.net/?f=%20Range%20%3D1.41-0.66%20%3D%200.75)
![\bar X = 1.171 W/Kg](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%201.171%20W%2FKg)
![s^2 = 0.0607](https://tex.z-dn.net/?f=%20s%5E2%20%3D%200.0607)
And taking the square root we got the sample deviation:
![s = \sqrt{0.0607}= 0.246 W/kg](https://tex.z-dn.net/?f=%20s%20%3D%20%5Csqrt%7B0.0607%7D%3D%200.246%20W%2Fkg)
Step-by-step explanation:
For this case we have the following datset given:
0.83 1.39 1.39 1.03 0.66 1.26 1.39 1.18 1.41 1.19 1.15
We need to find the range, and the range is defined by:
![Range = Max -Min](https://tex.z-dn.net/?f=%20Range%20%3D%20Max%20-Min)
And replacinng we got:
![Range =1.41-0.66 = 0.75](https://tex.z-dn.net/?f=%20Range%20%3D1.41-0.66%20%3D%200.75)
Then we can find the sample variance, but firt we need to find the sample mean with this formula:
![\bar X = \frac{\sum_{i=1}^n X_i}{n}](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20X_i%7D%7Bn%7D)
And replacing we got:
![\bar X = 1.171 W/Kg](https://tex.z-dn.net/?f=%20%5Cbar%20X%20%3D%201.171%20W%2FKg)
Now we can find the sample variance with this formula:
![s^2 = \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}](https://tex.z-dn.net/?f=%20s%5E2%20%3D%20%5Cfrac%7B%5Csum_%7Bi%3D1%7D%5En%20%28X_i%20-%5Cbar%20X%29%5E2%7D%7Bn-1%7D)
And replacing we got:
![s^2 = 0.0607](https://tex.z-dn.net/?f=%20s%5E2%20%3D%200.0607)
And taking the square root we got the sample deviation:
![s = \sqrt{0.0607}= 0.246 W/kg](https://tex.z-dn.net/?f=%20s%20%3D%20%5Csqrt%7B0.0607%7D%3D%200.246%20W%2Fkg)
Answer:
24
Step-by-step explanation:
To answer this you simply need to divide 6 by 1/4
or
6÷1/4
which is also equivalent to 6*4
this will get you 24
2x +8=2x+8
2x-2x=8-8
0x=0
So the answer is 0
y = mx + b
m = slope and b = y-intercept
We can arrange 6y = x - 12 in the form of y = mx + b
6y = x - 12
y = 1/6(x) - 2
Slope of y = 1/6(x) - 2 is 1/6. Taking the negative reciprocal of the slope we get the slope for the perpendicular line.
Negative reciprocal of 1/6 is -6.
The equation for the perpendicular line is
y = -6x + b
To find b we can plug in the x and y values of (4,-4) into it since it passes through those coordinates
-4 = -6(4) + b
b = -4 + 6(4)
b = -4 + 24
b = 20
So the equation for the perpendicular line is y = -6x + 20