Answer:
C) $58,544
Step-by-step explanation:
the yearly tuition is $58,830 minus her scholarship of $44,194 leaves her with $14,636 to come up with so $14,636 times 4 equals $58,544
she needs $58,544 to attend this university for four years.
hope this helps!
Answer: 5 branches and 16 birds.
Step-by-step explanation:
If the number of birds is B, and the number of branches is N.
First we have the equation:
B = 3*N + 1
(3 birds per branch + 1 that was flying around)
for the second equation we have:
B = 4*(N - 1)
(4 birds per branch, but one branch had no birds on it, so there are N -1 branches used)
now we can write:
3*N + 1 = 4*(N - 1)
3*N + 1 = 4*N - 4
4 + 1 = 4*N - 3*N
5 = N
So we had 5 branches, now we can replace it in one of the equations and find the number of birds.
B = 3*N + 1 = 3*5 + 1 = 16
Step-by-step explanation:
the answer is in the image above
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
First, determine the circumference (C) of the circle, the equation,
C = 2πr
Substituting the value or the radius,
C = 2π ( 4) = 8π
The arc length is the product of the circumference and the ratio between the subtended angle and 360. The mathematical expression is already,
S = (8π) x (72 / 360) = 0.8π
Thus, the arc is 0.80π.
