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Semenov [28]
3 years ago
8

Send help ??? please

Mathematics
2 answers:
ch4aika [34]3 years ago
8 0

Answer: One solution

Step-by-step explanation:

The two lines only intersect at one point, (-9,-23)

Trava [24]3 years ago
8 0
Answer - one solution -

The explanation is what he basically said
You might be interested in
In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
4 years ago
HELP ME PLEASE . IF YOURE GOOD GEOMETRY HELP
Art [367]
Oh these are easy, I’ll explain.
To start off, the answer is 11.
I got this by subtracting DE (57) and BC (35). You get 22. Then, you divide the result of the subtraction by 2, which is 11.
Let me know if you need me to explain in more depth, and give brainliest if I’m correct tysm.
4 0
3 years ago
Barbara plotted an elevation below sea level on a number line and labeled it A. She plotted point B above 0, a distance that is
PSYCHO15rus [73]
B is twice as far away from point A as it is from point 0.
7 0
3 years ago
Read 2 more answers
What are the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2?
Dmitry_Shevchenko [17]

The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

<h3>How to determine the potential zeros of the function f(x)?</h3>

The function is given as:

f(x)=6x^4+ 2x^3 - 4x^2 +2

For a function P(x) such that

P(x) = ax^n +...... + b

The rational roots of the function p(x) are

Rational roots = ± Possible factors of b/Possible factors of a

In the function f(x), we have:

a = 6

b = 2

The factors of 6 and 2 are

a = 1, 2, 3 and 6

b = 1 and 2

So, we have:

Rational roots = ±(1, 2)/(1, 2, 3, 6)

Split the expression

Rational roots = ±1/(1, 2, 3, 6)/ and ±2/(1, 2, 3, 6)

Evaluate the quotient

Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 1, 2/3, 1/3)

Remove the repetition

Rational roots = ±(1, 1/2, 1/3, 1/6, 2, 2/3)

Hence, the potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

The complete parameters are:

The function is given as:

f(x) = 3x^3 + 2x^2 + 3x + 6

The potential zeros of f(x)=6x^4+ 2x^3 - 4x^2 +2 are ±(1, 1/2, 1/3, 1/6, 2, 2/3)

Read more about rational roots at

brainly.com/question/17754398

#SPJ1

4 0
2 years ago
Is Y rational? Explain.
elena-14-01-66 [18.8K]
Yes
Explanation: because I’m SMART ☺️
4 0
3 years ago
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