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Ilya [14]
3 years ago
9

Susan made chocolate chip cookies, peanut butter cookies, and sugar cookies to sell at the bake sale. she made twice as many sug

ar cookies as peanut butter cookies, and she made one dozen more of chocolate chip cookies than sugar cookies. if she made a total of 11 dozen cookies, how many dozens did she make of each type of cookie?
Mathematics
2 answers:
Anestetic [448]3 years ago
5 0
Its B 2p=s s +1=c c+p+s=11
Romashka-Z-Leto [24]3 years ago
5 0

Answer: There are 2 dozens of peanut butter cookies, 4 dozens of sugar cookies and 5 dozens of chocolate chip cookies.

Step-by-step explanation:

Since we have given that

Susan made chocolate chip cookies, peanut butter cookies and sugar cookies to sell at the bake sale.

Let number of chocolate chip cookies be c

Let the number of peanut butter cookies be p

Let the number of sugar cookies be s

Total number of cookies = 11 dozen

Our equation will be

c+p+s=11

According to question, we have that she made twice as many sugar cookies as peanut butter cookies,

So,

s=2p

And she one dozen more of chocolate chip cookies than sugar cookies,

c=s+1\\\\c=2p+1

So, we have

c+s+p=11\\\\2p+1+p+2p=11\\\\5p+1=11\\\\5p=11-1\\\\5p=10\\\\p=\frac{10}{5}\\\\p=2

So,

s=2p=2\times 2=4\\\\and\\\\c=2p+1=2\times 2+1=4+1=5

So, there are 2 dozens of peanut butter cookies, 4 dozens of sugar cookies and 5 dozens of chocolate chip cookies.

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<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

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