This problem is about the distance between points, in this case, we have to unidimensional coordinates, that is, point O is at -2, and Point V is at 1/2.
It's important to know that the proper way to find the distance here is by subtraction, we need to subtract the final points and the initial point. In math, such subtraction is called "differential" or "variation", just a fancy name.
<h2>Therefore, the distance from O to B is 2.5 units.</h2>
Answer:
Step-by-step explanation:
1) Lines that are perpendicular have slopes that are opposite reciprocals of each other. y = -1/2x - 8 is in y = mx + b form, in which the number in place of m represents the slope. So, the slope of y = -1/2x - 8 is -1/2. The opposite reciprocal of it would be (remember to flip the fraction and reverse the sign) 2. So, 2 is the slope we need for the answer.
2) When you know a point that the line must pass through and its slope, you can use point-slope form () to write an equation. and represents the x and y values of the point the line intersects, and m represents the slope. So, substitute 2 for m, 7 for , and -6 for .
Answer:
p = -2, r = -2 and p-r = 0.
Step-by-step explanation:
(x - 1/2)(x - 2)
= x^2 - 2x - 1/2x + 1
= x^2 - 5/2x + 1
= 2x^2 - 5x + 2
= -2x^2 + 5x - 2
Comparing this with
px^2 + 5x + r
we see that p = -2, r = -2 and p-r = 0.
Answer:
y(x) = c_1 x
Step-by-step explanation:
Solve the separable equation x ( dy(x))/( dx) - y(x) = 0:
Solve for ( dy(x))/( dx):
( dy(x))/( dx) = y(x)/x
Divide both sides by y(x):
(( dy(x))/( dx))/y(x) = 1/x
Integrate both sides with respect to x:
integral(( dy(x))/( dx))/y(x) dx = integral1/x dx
Evaluate the integrals:
log(y(x)) = log(x) + c_1, where c_1 is an arbitrary constant.
Solve for y(x):
y(x) = e^(c_1) x
Simplify the arbitrary constants:
Answer: y(x) = c_1 x
Answer:
b 66
Step-by-step explanation: