The sum of two numbers s 21. The larger number is 6 less than twice the smaller number. Find the two numbers

Mathematics

2 answers:

xxMikexx [17]3 years ago

7 0

12 and 9 would be the answer

strojnjashka [21]3 years ago

6 0

Let the larger number be 'x' and smaller number be 'y'.

Since, the sum of two numbers is 21.

So, $x+y=21$ (equation 1)

Since, the larger number is six less than twice the smaller number.

So, $x=2y-6$ (equation 2)

Substituting the value of 'y' from equation 2 in equation 1.

So, $x+y=21$

$2y-6+y=21$

$3y = 27$

So, y=9.

Since, x+y=21

x = 21-y

x = 21-9

x = 12.

So, the larger number is 12 and smaller number is 9.

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6 0

2 years ago

What is 10.9091% to 2 decimal places

Tom [10]

Answer:

10.91%

Step-by-step explanation:

Take your number: 10.9091

Now find the first 3 decimals: 10.909

If the last (3rd) decimal is 5 or more raise the 2nd decimal: 10.909 → 10.91

That is 2 decimal places

(if your teacher doesn't want it rounded then just 10.90%)