Question

Belinda is jumping on a trampoline. She jumps up with an initial velocity (v0) of 17 feet per second. The function d(t) = v0t-16t^2 gives the height in feet of belinda above the trampoline as a function of time in seconds after her jump. How long after her jump will it take her to return to the trampoline again

Answer 1

Answer:

1.0625 seconds

Step-by-step explanation:

Given that:

Initial velocity of Belinda, $v_0=17\ ft/sec$

Height in feet of Belinda above the trampoline is given as the formula:

$d(t) = v_0t-16t^2$

Where $t$ is the time in seconds.

To find:

Time taken by Belinda to come back to trampoline = ?

Solution:

When Belinda will come back to trampoline, the height will be zero.

Putting $d(t) =0$

We have the equation as:

$0 = 17t-16t^2\\\Rightarrow 16t^2-17t=0\\\because t\neq0\\\Rightarrow 16t=17\\\Rightarrow t=\dfrac{17}{16}\\\Rightarrow t =1.0625\ seconds$

Therefore, the answer is: 1.0625 seconds