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Vinvika [58]
3 years ago
13

Belinda is jumping on a trampoline. She jumps up with an initial velocity (v0) of 17 feet per second. The function d(t) = v0t-16

t^2 gives the height in feet of belinda above the trampoline as a function of time in seconds after her jump. How long after her jump will it take her to return to the trampoline again
Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer:

<em>1.0625 seconds</em>

Step-by-step explanation:

Given that:

Initial velocity of Belinda, v_0=17\ ft/sec

Height in feet of Belinda above the trampoline is given as the formula:

d(t) = v_0t-16t^2

Where t is the time in seconds.

To find:

Time taken by Belinda to come back to trampoline = ?

Solution:

When Belinda will come back to trampoline, the height will be zero.

Putting d(t) =0

We have the equation as:

0 = 17t-16t^2\\\Rightarrow 16t^2-17t=0\\\because t\neq0\\\Rightarrow 16t=17\\\Rightarrow t=\dfrac{17}{16}\\\Rightarrow t =1.0625\ seconds

Therefore, the answer is: <em>1.0625 seconds</em>

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