Answer:
The minimum score required for recruitment is 668.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Top 4%
A university plans to recruit students whose scores are in the top 4%. What is the minimum score required for recruitment?
Value of X when Z has a pvalue of 1-0.04 = 0.96. So it is X when Z = 1.75.




Rounded to the nearest whole number, 668
The minimum score required for recruitment is 668.
The equation that represents a line that passed through (2,-1:2) and has a slope of 3 is y = 3x - 18
<h3>How to determine the equation of the line?</h3>
The points are given as:
(x1, y1) = (2, -12)
The slope is given as:
m = 3
The equation of the line is calculated using:
y = m(x - x1) + y1
So, we have:
y = 3(x - 2) - 12
Open the bracket
y = 3x - 6 - 12
Evaluate
y = 3x - 18
Hence, the equation of the line is y = 3x - 18
Read more about linear equations at:
brainly.com/question/1884491
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2 it’s two says the calculator
Answer:
Well there are 6 toppings. For one person to select sausage, it is \frac{1}{6} . For two people, multiply them together and the probability is \frac{1}{36}
First add what's in the parenthesis 1/2(3)(12)
then multiply 2 and 12 to get 1/2(36)
finally divide 36 by 2 and get 13