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svet-max [94.6K]

3 years ago

6

90 is one tenth of what?

1 answer:

Dafna1 [17]3 years ago

8 0

90 is a tenth of 900. You need ten 90's to make 900.

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1. Solve for the x and y intercepts:

aleksandrvk [35]

To find the x-intercept, you simply make y equal to 0 and solve the equation for x. To find the y-intercept, you make x equal to 0 and solve for y. So, for number 1, the answer is D because when you set it to y equals 0, you get x=3 and when you set it to x equals 0, you get 4.
Number 2 we would do the same thing and get D as well.
Hope this helps!

4 0

3 years ago

In a woodworking class, you need to make five triangles out of plywood. Each triangle has a height of 6 inches and a base of 14

Bogdan [553]

Answer:5 * (1/2 * 6 * 14)= x

Step-by-step explanation: :D

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3 years ago

In a poll of travelers, 85% said that traveling by air makes them nervous, and 450 travelers said that it does not make them ner

OverLord2011 [107]

The answer is 1,338 were polled

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3 years ago

Read 2 more answers

Rewrite each of the following sentences using logical connectives. Assume that each symbol!, x₀, n, x, B represents some fixed o

katrin [286]

Answer:

a) $(f\ has\ a\ relative \ minimum \ at\ x_{0} )$ ∧ $(f\ is\ differenciable\ at\ x_{0} )$ ⇒ $f^{'} (x_{0} )=0$ .

b) $(n\ is\ prime)$ ⇒ $(n=2)$ ∨ $(n\ is \ odd)$ .

c) $R\ is \ irreflexive\$ ⇒ $(R\ is\ symmetric)$ ∧ $(R\ is\ transitive)$ .

d) $detB=0$ ⇒ $(B \ is\ square)$ ∧ $(B\ is\ not\ invertible)$ .

e) $f\ has\ a\ critical\ point\ at \ x_{0}$ ⇔ $(f^{'}(x_{0})=0)$ ∨ $() \ f^{'}(x_{0}) \ does\ not\ exist$ .

f) $2n$ ∨ $n>4$ ⇒ $2$ .

g) $6\geq n-3$ ⇔ $n>4$ ∨ $n>10$ .

h) $x \ is \ cauchy$ ⇒ $x\ is\ convergent$ .

i) $\lim_{x \to \ x_{0}} f(x)=f(x_{0})$ ⇒ $f\ is\ continous\ at \ x_{0}$ .

j) $(f\ is\ diferenciable\ at\ x_{0})$ ∧ $(f\ is\ increasing\ at\ x_{0})$ ⇒ $f^{'}(x_{0})>0$ .

8 0

3 years ago

Help, how would I get my answer for this question?

Maslowich

Answer:

$(-4,32)$

Step-by-step explanation:

Given points are $(-1,-8)$

And given transformation is $D_4$ $r_{x-axis}$

We will start from left to right.

First transformation is reflection about x-axis.

When we reflect about x-axis $(x,y)\ became\ (x,-y)$

So, $(-1,-8)=[-1,-(-8)]=(-1,8)$

Now next transformation is dilation with a factor 4.

If we do dilation with a factor $'k'$ to the point $(x,y)$

New co-ordinates after dilation became $(kx,ky)$

So, $(-1,8)\ became\ (-4,32)$

8 0

3 years ago