Distance between A and B
= Distance between C and D
= sqrt((4 - 1)^2 + (5 - 2)^2)
= sqrt(3^2 + 3^2)
= sqrt(2 * 3^2)
= sqrt(3^2) * sqrt(2)
= 3sqrt(2)
Distance between B and C
= Distance between A and D
= sqrt((4 - 3)^2 + (5 - 0)^2)
= sqrt(1^2 + 5^2)
= sqrt(26)
Since sqrt(26) is more than 3sqrt(2), the length must be sqrt(26).
Hope this helps you.
Answer: n*4512 is less than or equal to 117
Step-by-step explanation: n=number N*45=X X=Number more than 117. X decreased by 12 is less than or equal to 117.
3(x-1)-8=4(1+x)+5
One solution was found :
x = -20
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
3*(x-1)-8-(4*(1+x)+5)=0
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((3•(x-1))-8)-(4•(x+1)+5) = 0
Step 2 :
Equation at the end of step 2 :
(3 • (x - 1) - 8) - (4x + 9) = 0
Step 3 :
Step 4 :
Pulling out like terms :
4.1 Pull out like factors :
-x - 20 = -1 • (x + 20)
Equation at the end of step 4 :
-x - 20 = 0
Step 5 :
Solving a Single Variable Equation :
5.1 Solve : -x-20 = 0
Add 20 to both sides of the equation :
-x = 20
Multiply both sides of the equation by (-1) : x = -20
One solution was found :
x = -20
hope this is wht u wanted
Answer:
see below
Step-by-step explanation:
|x - 3| < 4
To remove the absolute values, we need to make two inequalities, one positive and one negative
x-3 < 4 and x-3 > -4
Add 3 to each side
x-3+3<4+3 and x-3+3 > -4+3
x<7 and x >-1
-1 <x <7