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3 years ago

Draw the graph y = 4 x - 1 on the grid

Mathematics

1 answer:

kkurt [141]3 years ago

8 0

Answer:

From the graph, it is also clear that at $y=1$ , the value

of $x=\frac{1}{2}$ .

Step-by-step explanation:

Given the equation

$y = 4 x - 1$

The graph is attached below.

Putting $y=1$ in the equation to find the value of x

$y = 4 x - 1$

$1 = 4x-1$

$2 = 4x$

$x=\frac{2}{4}$

$x=\frac{1}{2}$

From the graph, it is also clear that at $y=1$ , the value

of $x=\frac{1}{2}$ .

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Is x = 1 a function?

Pie

Yes x = 1 is a function.
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3 years ago

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otez555 [7]

Answer:

There is no diagram for our observation. Please refine your question next time.

Step-by-step explanation:

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3 years ago

You are buying 12-packs of Mountain Dew for $\text{4.50}4.50 each and have a gift card worth $77. The function m\left(x\right)=4

poizon [28]

Answer:

$191

Step-by-step explanation:

The function is given by :

m(x) = 4.50x-7 ...(1)

Where

m(x) is the total cost if you buy x 12 packs of Mountain Dew.

We need to find the cost you pay to buy 44 12-packs of Mountain Dew

Put x = 44 in equation (1), we get :

m(x) = 4.50(44)-7

m(x) = 198-7

m(x) = $191

Hene, the cost for 44 12- packs of Mountain Dew is $191.

7 0

3 years ago

(2 points) The least squares method requires that the variance σ2????σϵ2 of the error variable ????ϵ is a constant no matter wha

attashe74 [19]

Answer:

C. heteroscedasticity

Step-by-step explanation:

The OLS regression assumption of error variance being constant irrespective of independent variables, is called Homoscedasticity.

Var (u | x) = σ^2 (u) ;

where u = error term, x = independent variable, σ^2 (u) = constant error variance

The violance of this assumption ie Var (u | x) is related to independent variable x, is called Heteroscedasticity.

6 0

4 years ago

g People between the ages of 65 and 70 were studied to see if those who exercise more were healthier. One measure of health was

liubo4ka [24]

Answer:

If the person selected had high blood pressure, the probability that he or she did not exercise is P=0.643.

Step-by-step explanation:

We have a group of people between agss of 65 and 70.

They are divided in two groups regarding their amount of exercise: "none", "moderate" and "high".

The response variable is blood pressure, that was categorized as "normal"or "high".

Then, we have the frequencies table as:

Amount of exercise None Moderate High

Blood pressure High 54 23 7

Blood pressure Normal 86 76 32

We have to calculate the probability that, given that the person had high blood pressure, he or she did not exercise.

If the person had high blood pressure, it can be of the any of the 3 groups of exercise amount. There are 54 people with high blood pressure that did not exercise, 23 that did moderate amount of exercise, and 7 that did a high amount.

Then, the probability can be calculated dividing the amount of people that had high blood pressure and did not exercise, by all the people that have high blood pressure (regarding the amount of exercise):

$P(N | HP)=\dfrac{54}{54+23+7}=\dfrac{54}{84}=0.643$

If the person selected had high blood pressure, the probability that he or she did not exercise is P=0.643.

5 0

3 years ago

Draw the graph y = 4 x - 1 on the grid​

Draw the graph y = 4 x - 1 on the grid