Question

In square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC. What is the ratio of the area of triangle AMN to the area of square ABCD? Express your answer as a common fraction.

Answer 1

Answer:

1:8

Step-by-step explanation:

Given that in square ABCD, point M is the midpoint of side AB and point N is the midpoint of side BC.

Let the side of the square be a.

Area of square ABCD = $a^2$

The triangle AMN is having two legs of a right triangle as half of side of the square

i.e. Triangle AMN has base = height = a/2

So area of triangle AMN = $\frac{1}{2} bh\\=\frac{a^2}{8}$

Ratio of the area of triangle AMN to area of square ABCD

= 1:8