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2 years ago

Fing the value of x, -3(2x-9)=3(16-x)

Mathematics

2 answers:

ololo11 [35]2 years ago

7 0

Answer:

x = -7

Step-by-step explanation:

First, we distribute, this gets us -6x+27 = 48-3x. Now, we add 3x to both sides, this gets us -3x+27 = 48. Now, we subtract 27 from both sides. -3x = 21. Now, we divide both sides by -3. This gets us x = -7.

Ksivusya [100]2 years ago

4 0

Answer:

x= -7

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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Pablo grew a plant for school and recorded the growth of the plant

Olenka [21]

Answer:

Yes. the relation is a function

Step-by-step explanation:

Here, we want to check if the relation is a function

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It is a function

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2 years ago

Imagine an experiment in which one student is selected at random from among all currently enrolled students in this university.

Alex_Xolod [135]

Answer:

$\left \{ x\varepsilon U;x\notin A \right \}$ , $\left \{ x\varepsilon U;x \varepsilon A\cap B \right \}$ , $\left \{ x\varepsilon U;x \notin A, x \varepsilon B \right \}$ , $\left \{ x\varepsilon U;x \notin A, x \notin B \right \}$ , $\left \{ x\varepsilon U;x \varepsilon A \cup B \right \}$ , $\left \{ x\varepsilon U;x \varepsilon (B-A)\cup (A-B) \right \}$

Step-by-step explanation:

Set refers to the well defined collection of objects.

We can express a set in set-builder form or in roaster form.

Roster form is a mathematical representation of a set that lists all of the elements of the set within the curly bracket, separated by commas.

A set-builder notation is a mathematical representation for describing a set that lists all of the elements of the set by stating the properties that its elements must satisfy.

Let A be the event that the selected student is classified as enrolled in engineering (one of the engineering schools), and let B be the event that the same student is currently enrolled in this class.

Let U denotes the set of all students currently enrolled in the university.

1. $\left \{ x\varepsilon U;x\notin A \right \}$

2. $\left \{ x\varepsilon U;x \varepsilon A\cap B \right \}$

3. $\left \{ x\varepsilon U;x \notin A, x \varepsilon B \right \}$

4. $\left \{ x\varepsilon U;x \notin A, x \notin B \right \}$

5. $\left \{ x\varepsilon U;x \varepsilon A \cup B \right \}$

6. $\left \{ x\varepsilon U;x \varepsilon (B-A)\cup (A-B) \right \}$

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2 years ago