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erastova [34]
3 years ago
14

At a lightbulb manufacturing plant, 2% of the lightbulbs are found defective. If the plant had 56 defective lightbulbs on a cert

ain day, how many did it manufacture that day?
Mathematics
1 answer:
svetlana [45]3 years ago
3 0

Answer:

2800 lightbulbs

Step-by-step explanation:

Divide 56 by 2% to cancel out the multiplication used to find the amount of defective lightbulbs.

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Can a line and a point be collinear
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Answer:

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Step-by-step explanation:

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Please show me the steps of 78.32/0.22
iragen [17]
Let's solve this problem step-by-step.

STEP-BY-STEP EXPLANATION:

Let's first establish the problem as the following:

= 78.32 / 0.22

First, we will make the deniminator a whole number. In order to accomplish this, we will multiply both the numerator and denominator in the fraction by 100.

= ( 78.32 × 100 ) / ( 0.22 × 100 )

= 7832 / 22

Next we will divide both the numerator and denominator by the highest common factor ( HCF ) of the two numbers in order to simplify the fraction fully.

The highest common factor of 7832 and 22 is 22.

HCF = 22

This means that we will divide both the numerstor and denominator of the fraction by 22.

= ( 7832 ÷ 22 ) / ( 22 ÷ 22 )

= 356 / 1

= 356

FINAL ANSWER:

Therefore, the answer is: 356.

Hope this helps! :)
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Step-by-step explanation:

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Read 2 more answers
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