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3 years ago

What is the probability of flipping a coin 10 times and getting heads four times Rania answer to the nearest 10th of a percent

Mathematics

1 answer:

EleoNora [17]3 years ago

4 0

Answer: 0.205

Step-by-step explanation:

The probability in one flip is equal to 0.5.

Now, if we do 10 flips, we want 4 times that the coin ends in heads and the other 6 times it must end in tails, so the probability is:

0.5^4*0.5^6 = 0.5^10

Now, this is the case where in the first 4 flips we get heads and in the other 6 we get tails, but we have other ways to get only 4 heads (for example in the last 4 flips, 2 at the beginning and 2 at the end, etc)

So we also need to calculate all the possible permutations of 4 heads in 10 flips. this is:

C = 10!/(10 - 4)!*4! = (10*9*8*7)/(4*3*2*1) = 210

So the probability that we are looking for is:

P = (0.5^10)*210 = 0.205

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3 years ago

Solve this for Brainliest! See the attachment [Level - GCSE]

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Answer:

$x = 3 + 4\sqrt{3}$

Step-by-step explanation:

OPQ is a right angle triangle.

Using Pythagoras

$x^{2} + (x+5)^{2} = (x+8)^{2}\\x^{2} + x^{2} + 10x +25 = x^{2} + 16x + 64\\x^{2} + x^{2} - x^{2} + 10x - 16x + 25 - 64 = 0\\x^{2} - 6x -39 = 0$

Using quadratic formula

$x = \frac{-b \± \sqrt{b^{2}-4ac}}{2a}\\x = \frac{-(-6) \± \sqrt{(-6)^{2}-4(1)(-39)}}{2(1)}\\x = \frac{6}{2} \± \frac{\sqrt{192}}{2}\\x = 3 \± \frac{8\sqrt{3}}{2}\\x = 3 \± 4\sqrt{3}$

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2 years ago

Read 2 more answers

Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi

den301095 [7]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31 or higher are significantly high

Step-by-step explanation:

Z-score:

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 20.6, \sigma = 5.2$