She would make $573.5 in a work if she sold $4,700 worth of merchandise
Step-by-step explanation:
The given is:
- Mae Ling earns a weekly salary of $315 plus a 5.5% commission on sales at a gift shop
- She sold by $4,700
We need to find how much she would make in a work week
∵ Mae Ling earns a weekly salary of $315
∵ She earns a 5.5% commission on sales
∵ She sold by $4,700 in that week
- Add $315 to the product of 5.5% and $4,700
∴ She made = 315 + (5.5% × 4,700)
∵ 5.5% = 5.5 ÷ 100 = 0.055
∴ She made = 315 + (0.055 × 4,700)
∴ She made = 315 + 258.5
∴ She made = 573.5
She would make $573.5 in a work if she sold $4,700 worth of merchandise
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Area of circle = πr²
Given that area = 153.86 m², find the radius:
153.86 = πr²
r² = 153.86 ÷ π
r² = 48.98
r = √48.98
r = 7 m
Diameter = Radius x 2 = 7 x 2 = 14 m
Answer: Diameter = 14 m
To find out how much Stan is paid a day, simply find out how many miles Stan drives per day, and multiply that with the amount Stan is paid per mile (in this case $3.50 per mile). Then, add that with the daily amount Stan earned (which is $75).
For example, on Monday, Stan drove a total of 30 miles (and he's paid $3.50 per mile).
Simply multiply $3.50 (per mile) with 30 (total number of miles driven), and that should equate to $105 earned for driving a total of 30 miles.
Then, add $105 (earned from driving 30 miles) to $75 (daily pay) and that equals $180.
Stan had been paid a total of $180 on Monday.
Answer: 56,058.42696629213
Answer:
Part 5) The length of the ski lift is 
Part 6) The height of the tree is 18.12 m
Step-by-step explanation:
Part 5)
Let
A -----> Beginning of the ski lift
B -----> Top of the mountain
C -----> Base of mountain
we have


----> by supplementary angles
Find the measure of angle B
Remember that the sum of the interior angles must be equal to 180 degrees

substitute

Applying the law of sines

substitute



Par 6)
see the attached figure with letters to better understand the problem
<u><em>Applying the law of sines in the right triangle BDC</em></u>
In the right triangle BDC 20 degrees is the complement of 70 degrees

-----> equation A
<u><em>Applying the law of sines in the right triangle ABC</em></u>
In the right triangle ABC 50 degrees is the complement of 40 degrees

-----> equation B
Equate equation A and equation B and solve for x

<u><em>Find the value of BC</em></u>


therefore
The height of the tree is 18.12 m