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Airida [17]
3 years ago
7

The area of a circle is 153.86 square meters. What is the diameter of the circle?

Mathematics
1 answer:
Yuliya22 [10]3 years ago
8 0
Area of circle = πr² 

Given that area = 153.86 m², find the radius:

 153.86 = πr²

r² = 153.86 ÷ π

r² = 48.98

r = √48.98

r = 7 m

Diameter = Radius x 2 = 7 x 2 = 14 m

Answer: Diameter = 14 m



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Solve the equation: 3x − x − 5 = 2(x + 2) − 9 No solution, 1, All real numbers, 0
Svetradugi [14.3K]

Answer:

I hope this helps

Step-by-step explanation:

Simplifying

3x + -1x + -5 = 2(x + 2) + -9

Reorder the terms:

-5 + 3x + -1x = 2(x + 2) + -9

Combine like terms: 3x + -1x = 2x

-5 + 2x = 2(x + 2) + -9

Reorder the terms:

-5 + 2x = 2(2 + x) + -9

-5 + 2x = (2 * 2 + x * 2) + -9

-5 + 2x = (4 + 2x) + -9

Reorder the terms:

-5 + 2x = 4 + -9 + 2x

Combine like terms: 4 + -9 = -5

-5 + 2x = -5 + 2x

Add '5' to each side of the equation.

-5 + 5 + 2x = -5 + 5 + 2x

Combine like terms: -5 + 5 = 0

0 + 2x = -5 + 5 + 2x

2x = -5 + 5 + 2x

Combine like terms: -5 + 5 = 0

2x = 0 + 2x

2x = 2x

Add '-2x' to each side of the equation.

2x + -2x = 2x + -2x

Combine like terms: 2x + -2x = 0

0 = 2x + -2x

Combine like terms: 2x + -2x = 0

0 = 0

Solving

0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

3 0
3 years ago
What three consecutive even integers have a sum of 78
Airida [17]

Answer:

24,26,28

Step-by-step explanation:

78 divided by 3 is 26, which means that 26 is the middle number and the next even number that is lower and bigger are the other two integers. You divide it by 3 because it's 3 consecutive even intergers

8 0
3 years ago
What is the length of ST
kupik [55]
The length of ST is 17
7 0
3 years ago
What is 7 over (fraction bar) (8×4)+90÷9 ÷ (6^3)^-2 × 9 over (fraction bar) 6(5+4) = ?????
amid [387]
The answer is:  " 36 " .
_______________________________
Note:  " (8 * 4) + 90 ÷ 9 " =  " (8 * 4) + (90 ÷ 9) " = "32 + 10 = 42" .

We can rewrite the "fraction":
 
7 / [ (8 * 4) + 90 ÷ 9 ] ;  as:  \frac{7}{42} ;  

and can reduce this value to (and rewrite as):  " \frac{1}{6} " ; 
    { since:  " \frac{7}{42}  =  \frac{7/7}{42/7}  = \frac{1}{6}" .}.

Note:  The "fraction" : \frac{9}{6(5+4)} ;  the "9/6" cancel to "3/2" ; 
  {Since:  "9÷3 = 3" ; and since:  "6÷3 = 2" ).

So rewrite:  \frac{9}{6(5+4)} ; as:  

\frac{3}{2(5+4)} ;

Note:  \frac{3}{2(5+4)}  ;

       =   \frac{3}{2(9)} ;

       =   \frac{3}{18} ;

→  Note:   \frac{3}{18} ;  can be reduced to; & rewritten as:

             " \frac{1}{6} " ;

→ {since: " \frac{3}{18} =  \frac{3/3}{18/3} ;
               
                                                      =   \frac{1}{6} ;
______________________________

Note that: (6²) ⁻² = 6⁽ ² * ⁻²⁾ = 6⁻ ⁴  ;
    
                            =  \frac{1}{6^4} ;
_________________________________________________________
So, we can rewrite our expression as:

 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;
_________________________________________________________
Note:  
_________________________________________________________
 \frac{1}{6}  ÷  \frac{1}{6^4}  *  \frac{1}{6} ;

= ( \frac{1}{6}  ÷  \frac{1}{6^4} ) *  \frac{1}{6} ; 

= ( \frac{1}{6}  *   \frac{6^4}{1} ) *  \frac{1}{6} ;

________________________________________________________
Start with :
________________________________________________________
   → ( \frac{1}{6}  *   \frac{6^4}{1} ) ;

            The "6" in  the  " \frac{1}{6} " ;  cancels to a "1" ; 
       and the "6⁴ " in the "  \frac{6^4}{1} ) " ; cancels to a "6³ " ;

         → {Since:  "6⁴ / 6  =  6⁴ / 6¹  =  6⁽⁴ ⁻ ¹⁾  = 6³ ;

         → and we have:   \frac{1}{1}  *  \frac{6^3}{1} ;
 
         →  The " \frac{1}{1} " can be eliminated; since "1÷1= 1 " ;
               and since: any value, divided by "1", equal that same value; & since "any                       value, multiplied by "1"; equals that same value" ;
________________________________________________________
 We have:  " 6³ " .
________________________________________________________

Now, we multiplied this value, " 6³ " , by  " \frac{1}{6} " ;

→  6³  *  \frac{1}{6}  ;

     =  \frac{6^3}{1} * \frac{1}{6}  ;

Note:  The "6³ " cancels out to "6² " ;  and the "6" cancels out to "1" ; 

          {since:  "6³ ÷ 6 = 6³ ÷ 6¹ = 6⁽³ ⁻ ¹⁾ = 6² " ;
            and since:  "6 ÷ 6 = 1 "  ; ________________________________________________________
→ The answer is:  6² = 6 * 6 = 36 ;
________________________________________________________
The answer is:  " <span>36 " .</span>
________________________________________________________
7 0
3 years ago
Please help me, this is due in 2 hours!! :-)
erastovalidia [21]
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6 0
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