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3 years ago

Find the value of x ANSWER IS NOT

Mathematics

2 answers:

Katen [24]3 years ago

7 0

Answer:

11sqrt(2)

Step-by-step explanation:

This is an isosceles right triangle so x=y.

By Pythagorean Theorem, x^2+x^2=22^2.

2x^2=22^2 after combining like terms

x^2=22^2 /2 after dividing 2 on both sides

x=sqrt(22^2 /2) after taking square root of both sides

x=22/sqrt(2)

x=22/sqrt(2) sqrt(2)/sqrt(2)

x=22sqrt(2)/2

x=11sqrt(2)

gulaghasi [49]3 years ago

3 0

Answer:

x = 11√2

Step-by-step explanation:

We can notice the triangle given is a special triangle, a 45°- 45°- 90° triangle. The hypotenuse of a 45°- 45°- 90° is √2 times the length of a side. We can set up the equation(using x as the side):

x * √2 = 22

We can divide by √2 on both sides to get:

x = 22 / √2

To rationalize the denominator, we multiply by √2 / √2 on the right side:

x = 22√2 / 2

This simplifies to:

x = 11√2

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Answer:

case a) $x^{2}=3y$ ----> open up

case b) $x^{2}=-10y$ ----> open down

case c) $y^{2}=-2x$ ----> open left

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Step-by-step explanation:

we know that

1) The general equation of a vertical parabola is equal to

$y=a(x-h)^{2}+k$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open upward and the vertex is a minimum

If a<0 ----> the parabola open downward and the vertex is a maximum

2) The general equation of a horizontal parabola is equal to

$x=a(y-k)^{2}+h$

where

a is a coefficient

(h,k) is the vertex

If a>0 ----> the parabola open to the right

If a<0 ----> the parabola open to the left

Verify each case

case a) we have

$x^{2}=3y$

$y=(1/3)x^{2}$

$a=(1/3)$

$a>0$

therefore

The parabola open up

case b) we have

$x^{2}=-10y$

$y=-(1/10)x^{2}$

$a=-(1/10)$

$a$

therefore

The parabola open down

case c) we have

$y^{2}=-2x$

$x=-(1/2)y^{2}$

$a=-(1/2)$

$a$

therefore

The parabola open to the left

case d) we have

$y^{2}=6x$

$x=(1/6)y^{2}$

$a=(1/6)$

$a>0$

therefore

The parabola open to the right

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