All categories

3 years ago

9×10^7 is how many times as large as 3×10^3? A.3×10^4. B. 27×10^4. C. 3×10^10. D. 27×10^10

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

3 0

Answer:

3x10^4

Step-by-step explanation:

9x10^7 = 3^2 x 10^7

3^2 : 3 = 3

10^7 : 10^3 = 10^4

The answer is :

3x10^4

You might be interested in

1+34n Square root 7 Need Help with question

pantera1 [17]

Answer:

what question is this

please explain more

Step-by-step explanation:

5 0

3 years ago

Shown below are the steps a student took to solve the simple interest formula A = P(1 + rt) for r.

asambeis [7]

To solve A = P(1 + rt) for r, first isolate (1 +rt) by dividing both sides of this equation by P:

A/P = 1 + rt.

Next, isolate rt by subtracting 1 from both sides:

A/P - 1 = rt

Finally, divide both sides by t:

A/P - 1

----------- = r

This could be written in other formats, such as:

A - P

-------- = r

7 0

3 years ago

Helpppp pleaseeeeeeeeeeeeeee

Vesna [10]

Answer:

Find below the calculations of the two areas, each with two methods. The results are:

Upper triangle:

$Area=5000\sqrt{3}units^2$

Lower triangle:

$Area=14,530m^2$

Explanation:

A) Method 1

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

$Area=side_1\times side_2\times sin(\alpha)$

Where, $\alpha$ is the measure of the included angle.

1. Upper triangle:

$side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2$

2. Lower triangle:

$side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2$

B) Method 2

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

$Area=(1/2)\times base\times height$

Use it for both triangles.

3. Upper triangle:

The trigonometric ratio that you can use is:

$sine(\alpha)=opposite\text{ }leg/hypotenuse$

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

$sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units$

$Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2$

3. Lower triangle:

$sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2$

$Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\ Area=14,529.96m^2\approx 14,530m^2$

5 0

3 years ago

Find the fractional form of 4.611 to prove that it is a rational number.

artcher [175]

Answer: 4611/1000
Move the decimal place until it is a whole number and if you moved it 3 places the denominator will have that much zeros

7 0

4 years ago

Solve for a: 3/5a = 1/4

NNADVOKAT [17]

Answer: $a=5/12$

Multiply both sides by 5/3

$(5/3)*(3/5a)=(5/3)*(1/4)\\a=5/12$

7 0

4 years ago

Read 2 more answers