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Agata [3.3K]
3 years ago
10

Find the value of x so that the function has the given value.

Mathematics
1 answer:
GuDViN [60]3 years ago
3 0

Answer:

-78

Step-by-step explanation:

-4/5+7;j(x0= -5

-4/5 equals 0.8

0.8 equals 80

-80+7= -73

-73 - -5= -78

X= -78

Please tell me if wrong

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12×2=24sq.ft.

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A copy of a line segment will have the same measure or length as the segment.

The true statement is (4) They are congruent.

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Hence, both lines are congruent, and the true statement is (d)

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Given trapezoid KLMN with midsegment EF, where KL = 4 and MN = 7, what is the length of EF?​
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Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
3 years ago
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