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mestny [16]
3 years ago
15

Use the parabola tool to graph the quadratic function y=-1? - 2.0 +8

Mathematics
1 answer:
Andreas93 [3]3 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

I don't have graphing facilities but can give you the vertex and 1 other point.

Given a parabola in standard form

y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

x = - \frac{b}{2a}

y = - x² - 2x + 8 ← is in standard form

with a = - 1 and b = - 2 , then

x = - \frac{-2}{-2} = - 1

Substitute x = - 1 into the equation for corresponding value of y

y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9

vertex = (- 1, 9 )

To obtain another point substitute any value for x into the equation

x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph

x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0  then (2, 0 ) is a point on the graph

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Let the equation be \frac{x^2}{a^2}+\frac{y^2}{b^2}=1
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3 years ago
Jon, Leroy, and Simon are having a free-throw shooting contest. Each boy
Zolol [24]

Answer:

B

Step-by-step explanation:

If you arrange a statistics in order from least to greatest, the middle number is the median.

If there is even number of numbers in a list, let it be n numbers, then we take the average of n/2th and n/2 + 1 th terms.

Here, all of them have 6 numbers, so 6/2 = 3  and 4th, we take average of 3rd and 4th number to find the median.

Since they are arrange in order we check each:

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a 34 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.137. find the substance's half-life, i
Ira Lisetskai [31]

Answer:

5.1 days

Step-by-step explanation:

Given in the question,

initial amount of substance = 34 grams

k-value = 0.137

To find the half life of this substance we will use following formula

N(0)/2 = N(0)e^{-kt}

here N(0) is initial amount of substance

        t is time in days

Plug values in the formula

34 /2 = 34e^{-0.137t}

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Take logarithm on both sides

ln(1/2) = ln( e^{-0.137t})

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t = ln(1/2) / -0.137

t = 5.059

t ≈ 5.1 days (nearest to tenths)

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