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GenaCL600 [577]
3 years ago
11

I need help fast!!!!!!!!

Mathematics
2 answers:
Stels [109]3 years ago
8 0

Answer: i wanna say its  C

Step-by-step explanation: i dont know please  dont be mad at me or hate me

3241004551 [841]3 years ago
5 0

Answer:

3rd

Step-by-step explanation:

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Limit (sin4x-4sinx)/x^3 when x close to zero
BartSMP [9]

\Large \boxed{\sf \bf \ \ \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}=-10 \ \  }

Step-by-step explanation:

Hello, please consider the following.

Using Maclaurin series expansion, we can find an equivalent of sin(x) in the neighbourhood of 0.

sin(x) \sim  \left(x-\dfrac{x^3}{3!}\right)\\\\\text{So, in the neighbourhood of 0}\\\\\begin{aligned}(sin(4x)-4sin(x)) &\sim \left( 4x-\dfrac{(4x)^3}{3!}-4x+\dfrac{4x^3}{3!}\right)\\\\&\sim \left(\dfrac{x^3*4*(1-4^2)}{3*2}\right)\\\\&\sim \left(\dfrac{x^3*2*(-15)}{3}\right)\\\\&\sim \left(x^3*2*(-5)\right)\\\\&\sim \left(x^3*(-10)\right)\\\end{aligned}

Then,

\displaystyle \lim_{x\rightarrow0} \ {\dfrac{sin(4x)-4sin(x)}{x^3}}\\\\= \lim_{x\rightarrow0} \ {\dfrac{-10*x^3}{x^3}}\\\\=-10

Thank you

4 0
4 years ago
Read 2 more answers
In order to solve the system of equations below, Harvey multiplies each equation by a constant to eliminate the x terms.
Karo-lina-s [1.5K]

Answer:

<u>The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77</u>

Step-by-step explanation:

Let's find out the constants to eliminate the x terms

7 x + 3 y = 5

2 x + 5 y = negative 11

Let's multiply the first equation by 2 and the second one by -7, this way:

2 * (7 x + 3 y = 5)

-7 * (2 x + 5 y = negative 11)

14x + 6y = 10

-14x - 35y = 77

<u>The correct answer is A. 14 x + 6 y = 10. Negative 14 x minus 35 y = 77</u>

5 0
3 years ago
Read 2 more answers
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