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2 years ago

Tom’s weekly salary increased from $240 to $300. What was the percent change?

Mathematics

2 answers:

s2008m [1.1K]2 years ago

8 0

Answer:

25% increase

Step-by-step explanation:

astraxan [27]2 years ago

3 0

Answer: 25%

Step-by-step explanation:

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Number:1,2,3,4,5,6 Frequency:4,6,x+5,x,2x,5 What is x and find the mean?

Paraphin [41]

Warning! Off topic question!

Step-by-step explanation:

I'm really sorry cuz this question has nothing to do with ur previous question. I just wanted to ask do u speak native German or fluent German cuz I have a very important test tomorrow and I'll really appreciate any help I can get. Sorry once again

4 0

3 years ago

Use completing the square to rewrite the equation in the form (x-h)^2 +(y-k)^2 = r^2. State the center (h, k) and radius r of th

Lisa [10]

Answer:

The equation is (x + 1)^2 + (y + 2)^2 = 15

Center is at (-1, -2) and radius = √15

Step-by-step explanation:

2x^2 + 2y^2 + 4x + 8y - 20 = 0

Divide through by 2:-

x^2 + y^2 + 2x + 4y - 10 = 0

x^2 + 2x + y^2 + 4x = 10

Completing the square on the x and y terms:-

(x + 1)^2 - 1 + (y + 2)^2 - 4 = 10

(x + 1)^2 + (y + 2)^2 = 10 + 1 + 4

(x + 1)^2 + (y + 2)^2 = 15

3 0

3 years ago

A restaurant uses 4.375 pounds of cheese for every pizzas. At this rate, how many pounds of cheese are used per pizza?

faltersainse [42]

<em><u>Complete Question:</u></em>

A restaurant uses 4.375 pounds of cheese every 8 and 3/4 pizzas. At this rate how many pounds of cheese are used per pizza?

<em><u>Answer:</u></em>

0.5 pounds of cheese are used per pizza

<em><u>Solution:</u></em>

Given that,

A restaurant uses 4.375 pounds of cheese every 8 and 3/4 pizzas

Therefore,

$4.375\ pounds = 8\frac{3}{4}\ pizza \\\\4.375\ pounds = \frac{35}{4}\ pizza$

We have to find pounds used per pizza

Let "x" be the pounds used per pizza

Then,

$4.375\ pounds = \frac{35}{4}\ pizza \\\\x\ pounds = 1\ pizza$

By cross multiplying,

$4.375 \times 1 = x \times \frac{35}{4} \\\\x = 0.5$

Thus, 0.5 pounds of cheese are used per pizza

8 0

3 years ago

Find the solutions to the equation 102x 11 = (x 6)2 – 2. Which values are approximate solutions to the equation? Select two answ

otez555 [7]

You can try finding the roots of the given quadratic equation to get to the solution of the equation.

There are two solutions to the given quadratic equation

$x = 0.202, x = 113.798$

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is $ax^2 + bx +c = 0$

Then its roots are given as:

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

<h3>How to find the solution to the given equation?</h3>

First we will convert it in the aforesaid standard form.

$102x + 11 = (x-6)^2 - 2\\102x + 11 + 2 = x^2 + 36 - 12x\\0 = x^2 -114x + 23\\x^2 -114x + 23 = 0\\$

Thus, we have

a = 1. b = -114, c = 23

Using the formula for getting the roots of a quadratic equation,

$x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{114 \pm \sqrt{114^2 - 92}}{2} \\\\ x = 0.202 (\text{used "-" sign})\\\\x = 113.798 ( used "+" sign})$