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attashe74 [19]
3 years ago
13

What is the absolute value of the complex number Negative 4 minus StartRoot 2 EndRoot i?

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0

Answer:

Step-by-step explanation:

-4-\sqrt{2}i \\ absolute ~value=\sqrt{(-4)^2+(-\sqrt{2} )^2} =\sqrt{18}=3\sqrt{2 }

Natali [406]3 years ago
5 0

Answer : The absolute value of the given complex is, 3\sqrt{2}

Step-by-step explanation :

As we know that,

The complex number is, a + bi

The absolute value = \sqrt{a^2+b^2}

Given :

The complex number -4-\sqrt{2}i.

For this complex number:

a = -4

b = -\sqrt{2}

Thus, the absolute value will be:

\sqrt{a^2+b^2}=\sqrt{(-4)^2+(-\sqrt{2})^2}=\sqrt{16+2}=\sqrt{18}=3\sqrt{2}

Thus, the absolute value of the given complex is, 3\sqrt{2}

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Which expression is not equivalent to Negative 3 x minus one-half 4 y? 2 y minus 5 x minus one-half 2 y 2 x Negative 2 x minus o
Alona [7]

Answer:

The wrt=itten expressions are too difficult to interpret properly.  I did my best but I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

Step-by-step explanation:

"Negative 3 x minus one-half 4 y"

-3x- (1/2)4y

<u>or -3x - 2y</u>

<u>=====</u>

The answer options are too garbled for me to make sense of them.  Are they:

1.  2 y minus 5 x minus one-half 2 y  :  2y -5x - (1/2)2y; <u>y -5x</u>  ?

2.  2 x Negative 2 x minus one-half 6 y :  2(-2x)- (1/2)6y; <u>-4x - 3y</u>  ?

3.  3 x Negative 3 x minus three-fourths 4 y :  3x(-3x) - (3/4)4y;  <u>-9x -3y</u>  ?

4.   one-fourth Negative 3 y minus three-fourths 7 y one-fourth minus 3 x:

     (1/4)(-3y) - (3/4)7y - (1/4)(-3x);  -(3/4)y -(21/4)y + (3/4)x; -(24/4)y +         (3/4)x;  ?

     

I don't see any of the answers as equivalent to <u>-3x - 2y, so please check my interpretations of the answer options.</u>

8 0
2 years ago
Read 2 more answers
Find the sum of first 15 terms of an AP whose 4th and 9th t terms are -15 and -30 respectively.
Serga [27]

Answer:

Sum of the first 15 terms = -405

Step-by-step explanation:

a + 3d = -15 (1)

a + 8d = -30 (2)

Where,

a = first term

d = common difference

n = number of terms

Subtract (1) from (1)

8d - 3d = -30 - (-15)

5d = -30 + 15

5d = -15

d = -15/5

= -3

d = -3

Substitute d = -3 into (1)

a + 3d = -15

a + 3(-3) = -15

a - 9 = -15

a = -15 + 9

a = -6

Sum of the first 15 terms

S = n/2[2a + (n − 1) × d]

= 15/2 {2×-6 + (15-1)-3}

= 7.5{-12 + (14)-3}

= 7.5{ -12 - 42}

= 7.5{-54}

= -405

Sum of the first 15 terms = -405

7 0
3 years ago
Help me out with the answer!!!!!!
Pie

Answer:

Adjacent

Step-by-step explanation:

8 0
3 years ago
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A line is drawn so that it passes through the points (-3, -1) and (4, 2).
marusya05 [52]

Answer:

y - 2 3/7 (x-4)

Step-by-step explanation:

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The slope of the line is 3/7.

B) Remember that the general equation for point-slope form is, where m = the slope,  = the x value of a coordinate point on the line, and  = the y value of the same coordinate point on the line.  

You are given (4, 2) as one of the coordinate points. That means  = 4 and  = 2. We found the slope, m =  in part A. Now plug these values into the general equation for point-slope form to find your point-slope form equation:

Your point-slope form equation is y - 2 3/7 (x-4).

4 0
3 years ago
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