Question

What is the absolute value of the complex number Negative 4 minus StartRoot 2 EndRoot i?

Answer 1

Answer:

Step-by-step explanation:

$-4-\sqrt{2}i \\ absolute ~value=\sqrt{(-4)^2+(-\sqrt{2} )^2} =\sqrt{18}=3\sqrt{2 }$

Answer 2

Answer : The absolute value of the given complex is, $3\sqrt{2}$

Step-by-step explanation :

As we know that,

The complex number is, a + bi

The absolute value = $\sqrt{a^2+b^2}$

Given :

The complex number $-4-\sqrt{2}i$.

For this complex number:

a = -4

b = $-\sqrt{2}$

Thus, the absolute value will be:

$\sqrt{a^2+b^2}=\sqrt{(-4)^2+(-\sqrt{2})^2}=\sqrt{16+2}=\sqrt{18}=3\sqrt{2}$

Thus, the absolute value of the given complex is, $3\sqrt{2}$