Answer:
Bag 3!
Step-by-step explanation:
GIVEN :
a = 1/√10 ( 3i + k) and
b = 1/7 ( 2i + 3j - 6k)
TO FIND :
( 2a- b) . [ ( a x b ) x ( a + 2b)]
SOLUTION :
◆Going with the equation given,
( 2a - b) . [ ( a x b ) x ( a + 2b)]
= (2a - b) [( a×b×a) + 2(a×b)×b]
◆BAC - CAB RULE,
A×B×C = B( A.B ) - C(A.B )
= (2a- b ) [ (b (a.a ) - a (a.b ) + 2b ( a.b) -2b (a.b]
Solving further
= (2a - b )(b - 2a)
= -4a.a -b.b
=-5.
Answer:
( 2 - b) . [ ( a x b ) x ( a + 2b)] = -5
Hoped I helped
Answer:
6x+20
c.
Step-by-step explanation:
If f(x)=6x+2 and you are asked to find f(x+3), then you just replace all the x's in f(x)=6x+2 with (x+3).
Doing this gives you:
f(x)=6x+2 with new input (x+3) in place of out input (x)
f(x+3)=6(x+3)+2
f(x+3)=6x+18+2
f(x+3)=6x+20
Answer:
n=13 s=-6
Step-by-step explanation:
Hope this helps :)
9t = 27.99
5t = ?
Cross-multiply : 9t? = 139.95t
?=15.55
