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3 years ago

12/6 = 4/2 true or false

Mathematics

2 answers:

alexandr402 [8]3 years ago

4 0

Answer:

This is true

Step-by-step explanation:

You are division by 12/6 by 3 and that =4/2

Lelechka [254]3 years ago

3 0

Answer:

true :)

Step-by-step explanation:

4 x 3 = 12 2 x 3 = 6

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A customer member owe 16.50 and pays $20 in cash the change due is 3.50 provide the amount owe using the smallest number of bill

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Answer:

Step-by-step explanation:

2 plus 6 is 8, 8 divided by 2 is 4

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3 years ago

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A rectangular prism has a volume of 100 cubic meters. One of the dimensions is 5 meters. Which pair of measurements could be the

natali 33 [55]

Answer:

1, 4, and 5

Step-by-step explanation:

1 is correct because 5*5=25*4=100

2 is incorrect because 5*5=25*5=125

3 is incorrect because 5*4=20*4=80

4 is correct because 5*20=100*1=100

5 is correct because 5*2=10*10=100

6 is incorrect because 5*10=50*10=500

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4 years ago

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which class is this because I am in 7th class so that's why I can't give

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3 years ago

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A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est

xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * $10^{-3}$ .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

X X - $Xbar$ $(X-Xbar)^{2}$

1.13 1.13 - 1.188 = -0.058 3.364 * $10^{-3}$

1.15 1.15 - 1.188 = -0.038 1.444 * $10^{-3}$

1.24 1.24 - 1.188 = 0.052 2.704 * $10^{-3}$

1.27 1.27 - 1.188 = 0.082 6.724 * $10^{-3}$

$\sum (X-Xbar)^{2}$ = 0.01568

Firstly, Mean of above data, $Xbar$ = $\frac{\sum X}{n}$ = $\frac{1.15+1.24+1.15+1.27+1.13}{5}$ = 1.188

Point estimate of Population Variance = Sample variance

= $\frac{\sum (X-Xbar)^{2}}{n-1}$ = $\frac{0.01568}{4}$ = 3.92 * $10^{-3}$ .

Therefore, point estimate for the population variance = 3.92 * $10^{-3}$ .

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3 years ago

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An employer has a staff of eighty actuaries, ten of whom are student actuaries. A student actuary is allowed a total of ten week

sergiy2304 [10]

Answer:

0.1111

Step-by-step explanation:

From the given information;

Number of staffs in the actuary = 80

Out of the 80, 10 are students.

i.e.

P(student actuary) = 10/80 = 0.125

number of weeks in a year = 52

off time per year = 10/52 = 0.1923

P(at work || student actuary) = (50 -10/52)

= 42/52

= 0.8077

P(non student actuary) = (80 -10)/80

= 70 / 80

= 0.875

For a non-student, they are only eligible to 4 weeks off in a year

i.e.

P(at work | non student) = (52-4)/52

= 48/52

= 0.9231

∴

P(at work) = P(student actuary) × P(at work || student actuary) + P(non student actuary) × P(at work || non studnet actuary)

P(at work) = (0.125 × 0.8077) + ( 0.875 × 0.9231)

P(at work) = 0.1009625 + 0.8077125

P(at work) = 0.90868

Finally, the P(he is a student) = (P(student actuary) × P(at work || student actuary) ) ÷ P(at work)

P(he is a student) = (0.125 × 0.8077) ÷ 0.90868

P(he is a student) = 0.1009625 ÷ 0.90868

P(he is a student) = 0.1111

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3 years ago