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2 years ago

Write the coefficient of x² in X/3 (6x-1/2)

Mathematics

2 answers:

Igoryamba2 years ago

7 0

Answer:

The coefficient of x² in the expression is 2

x/3(6x-1/2) = 6x²/3 - x/6

= 2x² - x/6

Hope this helps

frez [133]2 years ago

5 0

$\frac{x}{3}*(6x-\frac{1}{2} )=\frac{6x^{2} }{3}-\frac{x}{6}=2x^{2}-\frac{1}{6}x\\ coefficient is 2$

coefficient is 2

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Match each system of linear equations to its solution. A. (5, –6) b. (–2, 8) c. no solution d. (3, 1) e. (2, –8) f. (4, –1) g. i

almond37 [142]

Answer:

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Step-by-step explanation:

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2 years ago

Is the function even or odd?

sweet [91]

Answer:

$f(\theta)=\cos(\theta)$ is an even function.

Step-by-step explanation:

Recall when it means when a function is even or odd. An even function has the following property:

$f(-x)=f(x)$

And an odd function has the following property:

$f(-x)=-f(x)$

So, let's test some values for cos(x).

Let's use π/3:

$f(\pi/3)=\cos(\pi/3)$

From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).

Now, let's find -π/3. This is the same as 5π/3. Thus:

$f(-\pi/3)=\cos(-\pi/3)$

And again from the unit circle, we can see that this is 1/2.

Therefore, despite the negative, the function outputs the same value.

Cosine is an even function.

Notes:

Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!

6 0

2 years ago

I need help with 14 and 15

bekas [8.4K]

Answer:

14: 9 + 5 ℎ

15: − 1 6 + 9/ 9

Step-by-step explanation:

14 : ℎ ⋅ 5 + ( 9 )

5ℎ+ (9)

^^ Re-order terms so constants are on the left

5ℎ+ ⋅ 9 also 5 ℎ+9 then after this you would wanna re arange the terms so it would be 9 + 5 ℎ

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2 years ago

Write Each Number As A Power Of 5

Lena [83]

The numbers as powers of 5 are 5^-1, 5^-2, 5^-3 and 5^0

<h3>How to rewrite the numbers as a power of 5?</h3>

The numbers are given as:

• 0.2

• 0.04

• 125^-1

• 15^0

<u>Number 1: 0.2</u>

Express as fraction

1/5

Apply the power rule of indices

5^-1

<u>Number 2: 0.04</u>

Express as fraction

1/25

Express 25 as 5^2

1/5^2

Apply the power rule of indices

5^-2

<u>Number 3: 125^-1</u>

Express as fraction

1/125

Express 125 as 5^3

1/5^3

Apply the power rule of indices

5^-3

<u>Number 4: 15^0</u>

Evaluate the exponent

15^0 = 1

Express 1 as 5^0

15^0 = 5^0

Hence, the numbers as a power of 5 are 5^-1, 5^-2, 5^-3 and 5^0