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nevsk [136]
2 years ago
11

What number can 330 and 180 both be divided by?? Plz help

Mathematics
2 answers:
Katena32 [7]2 years ago
7 0

Answer:

1, 2, 3, 5, 6, 10, 15, and 30

Step-by-step explanation:

all of these are factors of both

Pls Give Brainliest

Ksju [112]2 years ago
4 0

Answer:

330 and 180 have 8 common factors (divisors):

1; 2; 3; 5; 6; 10; 15 and 30

out of which 3 prime factors: 2; 3 and 5

Step-by-step explanation:

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NEED HELP . GIVING BRAINLIEST
andreev551 [17]

Answer:

There are 108 inches in 9 feet

Step-by-step explanation:

Well, two unit multipliers mean we have to convert through two units before we arrive at our final answer so we can convert from feet to yards to inches!

We know that 3 feet equal a yard, right?

So we can divide 9 by 3 to get the amount that 9 feet translates to in yards.

9/3 = 3!

So we are now done with our first conversion! Our second is going to be from yards to inches!

There are 36 inches in 1 yard so we should multiply 3 by 36 to get the amount in inches!

3*36 = 108!

4 0
3 years ago
Please help. Dont put a random answer plz.
Alenkasestr [34]

Answer:

Explination:

Work:

5 0
3 years ago
Mr.Montgomery's class, there are 8 boys and 12 girls.If Mr.Montgomery selects 1 student from his class at random, what is the pr
Gnoma [55]
Probability=number of specific outcomes / total possible outcomes

P(g)=12/(12+8)

P(g)=12/20

P(g)=3/5
7 0
2 years ago
Square root of 50 + square root of 18
skelet666 [1.2K]

if ya asking for simpliicatio

remember that \sqrt{ab}=(\sqrt{a})(\sqrt{b})

and

\sqrt{a^2}=(\sqrt{a})(\sqrt{a})=a

\sqrt{50}+\sqrt{18}=

factor

(\sqrt{2})(\sqrt{5})(\sqrt{5})+(\sqrt{2})(\sqrt{3})(\sqrt{3})=

(\sqrt{2})(5)+(\sqrt{2})(3)=

5\sqrt{2}+3\sqrt{2}=

8\sqrt{2}

5 0
3 years ago
Write the equation of the line that passes through the points (-6,-1) and (-4,2). Put your answer in fully simplified point-slop
Archy [21]

(\stackrel{x_1}{-6}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{-4}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{2}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{-4}-\underset{x_1}{(-6)}}} \implies \cfrac{2 +1}{-4 +6} \implies \cfrac{ 3 }{ 2 }

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{\cfrac{3}{2}}(x-\stackrel{x_1}{(-6)}) \implies {\large \begin{array}{llll} y +1= \cfrac{3}{2} (x +6) \end{array}}

4 0
1 year ago
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