Someone help me on 1 pls

Solve the equation.<br> x² =96<br><br> A 4/6<br><br> B 16/6<br><br> C 9<br><br> D 9,-9

alexgriva [62]

Answer:

x = ± 4 $\sqrt{6}$

Step-by-step explanation:

Given

x² = 96 ( take the square root of both sides )

x = ± $\sqrt{96}$ = ± $\sqrt{16(6)}$ = $\sqrt{16}$ × $\sqrt{6}$ = ± 4 $\sqrt{6}$

3 0

3 years ago

What is the area of a sector with a central angle of (2pi/3) radians and a diameter of 12 in?

Stels [109]

Answer:

The area of the sector is $37.68\ in^{2}$

Step-by-step explanation:

step 1

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

we have

$r=12/2=6\ in$ ----> the radius is half the diameter

substitute

$A=(3.14)(6)^{2}$

$A=113.04\ in^{2}$

step 2

Find the area of a sector with a central angle of (2pi/3)

Remember that

The area of $113.04\ in^{2}$ subtends a central angle of $2\pi \ radians$

so

by proportion

Let

x----> the area of the sector

$\frac{2\pi}{113.04}=\frac{(2\pi/3)}{x}\\ \\x=113.04*(2\pi/3)/(2\pi)\\ \\x=37.68\ in^{2}$

8 0

3 years ago

If one end of a line segment is (4, 4) and midpoint is (-2,2), find the co-ordinates of the other end.

Soloha48 [4]

Answer:

-8,0

Step-by-step explanation:

From one end of a segment to the midpoint, it takes -6x to get to the midpoint. Based on that, you can go another 6 over the y graph and get -8 for x.

For y, the segment goes from 4 to 2 (a -2 over the x graph). you can infer then that the other end will be 0.

6 0

2 years ago

Zaheer, a boy of height 1.5m was watching the entire programme. Initially he observed the top of theflagpoleat an angle of eleva

torisob [31]

Answer:

$h = 15.163\ meters$

Step-by-step explanation:

(Assuming the correct angles are 30° and 45°)

We can use the tangent relation of the angle of elevation to find two equations, then we can use these equations to find the height of the pole.

Let's call the initial distance of the boy to the pole 'x'.

Then, with an angle of elevation of 30°, the opposite side to this angle is the height of the pole (let's call this 'h') minus the height of the boy, and the adjacent side to the angle is the distance x:

$tan(30) = (h - 1.5) / x$

Then, with an angle of elevation of 45°, the opposite side to this angle is still the height of the pole minus the height of the boy, and the adjacent side to the angle is the distance x minus 10:

$tan(45) = (h - 1.5) / (x - 10)$