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3 years ago

Select the property that is demonstrated by: 3+7=7+3

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

Answer:

Commutative property of addition

Step-by-step explanation:

This is called the commutative property of addition which states that a + b = b + a. In this case, a = 3 and b = 7.

wlad13 [49]3 years ago

3 0

Answer:Communitive Property of Addition

Step-by-step explanation:

A+B=B+A 3+7=7+3

The communitive property of addition states that the order of two numbers being added doesn’t matter and that the sum is the same.

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Ivan

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9C4 = 9! / 5! 4! = 9*8*7*6 / 4*3*2*1 = 126

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3 years ago

Determine whether the following statement is true or false. Then, use complete sentences to explain your answer. If you wish, yo

chubhunter [2.5K]

Answer:

False

Step-by-step explanation:

An acute angle can be scalene

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2 years ago

Mrs. Write makes cookies for the school bake sale. She uses the equation y=0.50x to determine the cost, y, for x cookies. Which

Anni [7]

Answer:D

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3 0

2 years ago

Let A = -4k+ 3 and B = 3k +17. If A = B, then what is the value of k?

kupik [55]

Answer:

k=-2

Step-by-step explanation:

Using substitution to find what you're missing, (in this case k) is when you plug each letter into the other equation:

-4k+3=3k+17

So now solve for k:

subtract 3 from both sides...

-4k=3k+14

subtract 3k from both sides to combine with -4k...

-7k=14

divide -7 from both sides...

k=-2

3 0

1 year ago

For what value of k will the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent?

konstantin123 [22]

Answer:

After solve the equations we get value of k=3

Step-by-step explanation:

We need to find value of k for which the lines x+2y=0, 3x-4y-10=0 and 5x+ky-7=0 are concurrent.

If the lines are concurrent, they pass through same point.

Let:

$x+2y=0--eq(1)\\ 3x-4y-10=0--eq(2)\\ 5x+ky-7=0--eq(3)$

First solving equation 1 and 2 to find values of x and y

From eq(1) we find value of x and put it in eq(2)

$From \ eq(1) x+2y=0\\x=-2y\\Put x=-2y \ in \ eq(2)\\3x-4y-10=0\\3(-2y)-4y-10=0 \\-6y-4y=10\\-10y=10\\y=\frac{10}{-10}\\y=-1$

After solving we get value of y=-1

Now putting in eq(1) to get value of x

$x+2y=0\\x+2(-1)=0\\x-2=0\\x=2$

So, Value of x= 2

Now put value of x=2 and y=-1 into eq(3) to find value of k

$5x+ky-7=0\\5(2)+k(-1)-7=0\\10-k-7=0\\-k+3=0\\-k=-3\\k=3$

So, After solve the equations we get value of k=3

4 0

2 years ago