Let
The origin of coordinates the tree
r1 = vector position of the child 1.
r2 = vector position of the child 2
Child 1:
r1 = (12i + 12j)
Child 2:
r2 = (-18i + 11j)
The scalar product will be given by:
r1.r2 = ((12) * (- 18)) + ((12) * (11)) = - 84
The scalar product of their net displacements from the tree is -84m ^ 2
Answer:
<h3><X = 63</h3>
Step-by-step explanation:
USing SOH CAH TOA
sin theta = opposite/hypotenuse
sin <X = WV/VX
sin <X = 8/9
<X = arcsin(8/9)
<X = arcsin(0.8889)
<X = 62.7 degrees
Hence the value of x is approximately 63degrees
1 m = 100 cm
1 m^3 = 1^6 cm^3
so 1 cm^3 = 10^-6 m^3
and 1 L = 1000 cm^3 = 10^-3 m^3
The equation for volume of a sphere is pi(r)^3 This mean that the equation would be pi(11)^3 which equals 1331pi
( 6 , 2)
in other words :
x = 6 , y = 2
