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GenaCL600 [577]
3 years ago
13

A cylinder has a radius of 5 centimeters

Mathematics
1 answer:
zaharov [31]3 years ago
6 0

SA for a cylinder = 2 pie r squared + 2 pie r h

= 2 x pie x 25 + 2 x pie x 5 x 17

= 220 pie or 690.8 if you use 3.14 instead of the full value

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Birthdays of hockey players: In Malcolm Gladwell’s book "Outliers" he shares the work of Canadian psychologist Roger Barnsley, w
alexgriva [62]

Answer:

The P-value is 0.009.

Step-by-step explanation:

We are given that after debating whether this set of hockey players can be viewed as a random sample of hockey players, they decide to run a hypothesis test anyway to practice finding the P‐value.

<em><u>We are given that the following hypothesis below;</u></em>

Null Hypothesis, H_0 : p = 0.25

Alternate Hypothesis, H_A : p > 0.25

Now, the test statistics that was used here for the above hypothesis would be;  

                       T.S.  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

Also, the test statistics given to us is 2.37.

<u></u>

<u>SO, the P-value of the test statistics is given by the following formula;</u>

             P-value = P(Z > 2.37) = 1 - P(Z \leq 2.37)

                           = 1 - 0.99111 = 0.00889 ≈ 0.009

<em>The above probability is calculated by looking at the value of x = 2.37 in the z table which has an area of 0.99111.</em>

Therefore, the required P-value is 0.009.

6 0
3 years ago
My number has two periods. One period contains the digit 3,0 and 6 in that order. The other contains the digits 0,9 and 5 in tha
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In a recent survey about the types of transportation used for vacation, 36% of the 200 people surveyed chose airplanes, 53% chos
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larisa86 [58]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Write the equation of a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2(sqrt5)
Xelga [282]

Answer:

\frac{x^2}{16}-\frac{b^2}{4}=1

Step-by-step explanation:

A hyperbola is the locus of a point such that its distance from a point to two points (known as foci) is a positive constant.

The standard equation of a hyperbola centered at the origin with transverse on the x axis is given as:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

The coordinates of the foci is at (±c, 0), where c² = a² + b²

Given that  a hyperbola centered at the origin with x-intercepts +/- 4 and foci of +/-2√5. Since the x intercept is ±4, this means that at y = 0, x = 4. Substituting in the standard equation:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\frac{4^2}{a^2}-\frac{0}{b^2} =1\\\frac{4^2}{a^2}=1\\ a^2=16\\a=\sqrt{16}=4\\ a=4

The foci c is at +/-2√5, using c² = a² + b²:

c^2=a^2+b^2\\(2\sqrt{5} )^2=4^2+b^2\\20 = 16 + b^2\\b^2=20-16\\b^2=4\\b=\sqrt{4}=2\\ b=2

Substituting the value of a and b to get the equation of the hyperbola:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1\\\\\frac{x^2}{16}-\frac{b^2}{4}=1

5 0
3 years ago
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