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2 years ago

Solve -7(s+2)-12=37 What is s

Mathematics

2 answers:

N76 [4]2 years ago

6 0

Answer:

S = -9

Click on photo for steps

Shkiper50 [21]2 years ago

4 0

Answer:

s= -5.57 (rounded to the nearest hundredth)

Step-by-step explanation:

1. Multiply s and 2 by 7.

You'll get -7s-14. We'll come back to this later

2. Subtract 12 from 37.

You'll get 25

3. Add 14 to both sides so that you cancel out the -14.

The equation stands as -7s= 39

4. Divide both sides by -7 so that we leave s by itself.

s= -5.57142857

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True or false: 4 (2x + y + 6) is equivalent to 8x + 4y + 24. A true B false

kenny6666 [7]

Answer:

A) true

Step-by-step explanation:

when you use the distributive property with the equation 4(2x + y + 6) you get 8x + 4y + 24

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3 years ago

Which statements about the graph of the function f(x) = -x - 4x + 2 are true? Select three options.

stich3 [128]

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2 years ago

What is 5(4x+7)=295 it is an equation

frutty [35]

Divide both sides by 5

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Subtract 7 on both sides

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2 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

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3 years ago

What is the domain and range of f(x)=2x-5

Mrrafil [7]

f(x) is a linear function with no restrictions

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2 years ago