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3 years ago

HURRY PLEASE I WILL GIVE BRAINLIEST

Mathematics

1 answer:

Sergeu [11.5K]3 years ago

7 0

Answer:

About 40% of students own a cat

Step-by-step explanation:

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Help please?

ziro4ka [17]

Answer:

cos(θ) = -1/2
tan(θ) = √3

Step-by-step explanation:

You know that ...

cos(θ)² = 1 - sin(θ)²
tan(θ) = sin(θ)/cos(θ)
cosine is negative in the third quadrant (where π < θ < 3π/2)

Using what you know about the relationships of these trig functions, you can find ...

cos(θ)² = 1 - ((-√3)/2)² = 1 - 3/4 = 1/4

cos(θ) = -1/2 . . . . . negative square root of 1/4

tan(θ) = sin(θ)/cos(θ) = ((-√3)/2)/(-1/2)

tan(θ) = √3

8 0

3 years ago

Answer this 2(3^2 + 4^2) = ?

Vikentia [17]

Answer:

Step-by-step explanation:

2(3^2+4^2)=

3^2/(3x3) = 9

4^2/(4x4) = 16

9+16=25

so.... rewritten it is

2(25)= or 2 x 25= 50

6 0

3 years ago

Use the ruler to measure the length of the colored pencils, then select the line plot that best represents this data set.

Marta_Voda [28]

Its the last line plot

4 0

3 years ago

Read 2 more answers

This list shows the lengths in feet of the 25 longest bridges in the United States.

Paladinen [302]

The length of the intervals of the given frequency table is

500 ft.

The given list shows the lengths in feet of the 25 longest bridges in the United States.

we have to determine the median and mode of the bridge data.

The median is the middle number of the data set arranged in ascending order.

1010, 1053, 1200, 1207, 1380, 1470, 1495, 1596, 1600, 1600, 1600, 1632, 1750, 1800, 1850, 2000, 2150, 2150, 2300, 2310, 2800, 3500, 3800, 4200, 4260.

The median is 1750.

Mode is the number that appears most often in the data set.

1010, 1053, 1200, 1207, 1380, 1470, 1495, 1596, 1600, 1600, 1600, 1632, 1750, 1800, 1850, 2000, 2150, 2150, 2300, 2310, 2800, 3500, 3800, 4200, 4260

The mode is 1600.

Therefore the correct option is Median: 1750, Mode: 1600

So the length of the intervals of the given frequency table is

500 ft.

To learn more about the frequency of visit:

brainly.com/question/301048

#SPJ1

7 0

2 years ago

An accounting machine operator wanted to divide an 85-minute job between two identical machines so that one machine would take o

Lubov Fominskaja [6]

To find how much time the machine that took the longer job is, you would create an equation in terms of X, the amount of time it takes one of the machines.

Please see the attached picture for the work.

51 minutes is the longer time.
34 minutes for the other machine.

6 0

3 years ago