Answer:
The ira will contain $228,278.05 when he retires at age 65. This is 6.04 times the amount of money he deposited.
Step-by-step explanation:
In order to solve this problem, we can make use of the following formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
Where:
FV= Future value of the ira
PMT= the amount of money you deposit each month
i= is the interest rate per period
n=number of periods
in this case we will assume the interest will be compounded each month.
So:
FV this is what we need to know.
PMT= $75 the amount he will deposit each month
t = 42 years,
this is 65-23=42
n=42 years * 12 months/year = 504 months
i=0.07/12
So we can now use the given formula:
![FV=PMT[\frac{(1+i)^{n}-1}{i}]](https://tex.z-dn.net/?f=FV%3DPMT%5B%5Cfrac%7B%281%2Bi%29%5E%7Bn%7D-1%7D%7Bi%7D%5D)
![FV=75[\frac{(1+\frac{0.07}{12})^{504}-1}{\frac{0.07}{12}}]](https://tex.z-dn.net/?f=FV%3D75%5B%5Cfrac%7B%281%2B%5Cfrac%7B0.07%7D%7B12%7D%29%5E%7B504%7D-1%7D%7B%5Cfrac%7B0.07%7D%7B12%7D%7D%5D)
So we get:
FV=$228,278.05
which is the amount of money he will have after 42 years.
In total, he deposited:
$75*504months = $37,800
so he will have:
times the amount of money he deposited throughout this time.



Maximum number of packets = 8
16 ÷ 8 = 2
There are 2 pencils in each packet.
24÷8 = 3
There are 3 erasers in each bag.
Rosy can have a maximum of 8 packets. Each packet has 2 pencils and 3 erasers.
It would be 4.8333333333.
The three repeats here.
Answer:
graph attached
Step-by-step explanation:
A graph is a pictorial representation that represent the relationship between two or more things.
Cosine function is periodic with period
. If the point
lies on the graph, point
will also lie on the graph where k is any integer.
Here,
![cos(x-\pi )=cos[-(\pi -x)]=cos(\pi -x)=-cos x](https://tex.z-dn.net/?f=cos%28x-%5Cpi%20%29%3Dcos%5B-%28%5Cpi%20-x%29%5D%3Dcos%28%5Cpi%20-x%29%3D-cos%20x)