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Andrej [43]
2 years ago
15

PLEASE HELP!!

Mathematics
1 answer:
viktelen [127]2 years ago
4 0

Answer:

C. The principal randomly selects homeroom classes and surveys each student in the chosen classes.

Step-by-step explanation:

Middle school is 6-8th. Surveying only the eighth-grade students won't give a representative sample of the whole school only the eighth-graders. Option A is incorrect.

Surveying only the students in detention represents a very small amount of students compared to the school, therefore it is not a representative sample. Option B is incorrect.

Yet again, the students in the math club is a small amount of students compared to the school. It does not represent the entire, or majority of the population. Option D is incorrect.

Picking students from homeroom classes and surveying each will give a wider variation of opinions from each grade and therefore a representative sample. Option C is the correct answer.

You might be interested in
If y varies directly as x, and y =6 when x =10, find x when y=18
bonufazy [111]

Answer:

X=30

Step-by-step explanation:

y=kx

6=10k

k=0.6

y=0.6x

18=0.6x

X=18/0.6

x=30

7 0
3 years ago
Aye someone please help ?
monitta

Answer:

The required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

Step-by-step explanation:

z_1=6[\cos (\frac{5\pi}{4}) + i\sin(\frac{5\pi}{4})]...........(1)\\\\Now,\cos (\frac{5\pi}{4})=\cos(\pi+\frac{\pi}{4})\\\\=-\cos(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}\\\\And,\sin (\frac{5\pi}{4})=\sin(\pi+\frac{\pi}{4})\\\\=-\sin(\frac{\pi}{4})\\\\=-\frac{1}{\sqrt{2}}

On substituting the obtained values in equation (1)

z_1=6[\frac{-1}{\sqrt{2}}-i\cdot \frac{1}{\sqrt{2}}]\\\\\implies z_1=-3\sqrt{2}- 3\sqrt{2}\cdot i

Hence, the required rectangular form of the given complex polar form :

z1 = -3√2 - 3√2i

7 0
3 years ago
Help giving brainliest to first answer!!
Shkiper50 [21]

Answer: It's C. The third one.

Step-by-step explanation:

HOPE THIS HELPS!!!! : )

8 0
3 years ago
Anyone know the answer?!
brilliants [131]

Answer:

a, 8,300

Step-by-step explanation:

6 0
3 years ago
How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati
Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0
1 year ago
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