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earnstyle [38]
2 years ago
11

Hi! I just need somebody to explain how this is done.

Mathematics
1 answer:
iren2701 [21]2 years ago
3 0

Answer:

Exact form: x = \frac{10.8}{sin(57)}

Rounded to the Nearest Tenth: x = 12.9

Step-by-step explanation:

<em>In the right-angled triangle, we can use the trigonometry functions to find the length of a side or a measure of an angle</em>

In the given figure

∵ ∠C is the right angle

∴ ΔACB is a right triangle

∵ m∠B = 57°

∵ AC = 10.8

∵ AC is the opposite side of ∠B

∵ AB is opposite to the right angle

∴ AB is the hypotenuse

∵ AB = x

→ We can use the function sine to find x

∵ sin∠B = \frac{opposite}{hypotenuse}

∴ sin∠B = \frac{AC}{AB}

→ Substitute the values of ∠B, AC, and AB in the rule of sine above

∴ sin(57°) = \frac{10.8}{x}

→ By using cross multiplication

∵ x × sin(57°) = 10.8

→ Divide both sides by sin(57°)

∴ x = \frac{10.8}{sin(57)}

∴ x = 12.87752356

→ Round your answer to the nearest tenth

∴ x = 12.9

Exact form: x = \frac{10.8}{sin(57)}

Rounded to the Nearest Tenth: x = 12.9

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yarga [219]
75 divided by 15 is 5. 5 eggs per hen
8 0
3 years ago
2(6k+8)-6k=4<br> What is the answer
lina2011 [118]

Answer:

k=-2

Step-by-step explanation:

2(6k+8)-6k=4

12k+16-6k=4

6k+16=4

6k=-12

k=-2

7 0
3 years ago
The sum of two numbers is 50 and their difference is 4 what are the two numbers
Deffense [45]

Answer:

27 and 23

Step-by-step explanation:

We can solve this problem as a system of equations. X is the first number and Y is the second number.

The first equation is x+y = 50 and the second equation is x-y=4

Now we solve the system, using elimination method:

x+y=50

x-y=4

2x = 54

x = 54/2

x = 27

And from any of the equations we can find Y

27 + y = 50

y = 50 - 27

y = 23

6 0
3 years ago
If A is nonsingular, then (AT )-1 =(A-1) T . (a) Verify this theorem for 2 × 2 matrices
kipiarov [429]

Answer:

Verified

Step-by-step explanation:

Let the 2x2 matrix A be in the form of:

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]

Where det(A) = ad - bc # 0 so A is nonsingular:

Then the transposed version of A is

A^T = \left[\begin{array}{cc}a&c\\b&d\end{array}\right]

Then the inverted version of transposed A is

(A^T)^{-1} = \frac{1}{ad - cb} \left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

The inverted version of A is:

A^{-1} = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-b\\-c&d\end{array}\right]

The transposed version of inverted A is:

(A^{-1})^T = \frac{1}{ad - bc}\left[\begin{array}{cc}a&-c\\-b&d\end{array}\right]

We can see that

(A^T)^{-1} = (A^{-1})^T

So this theorem is true for 2 x 2 matrices

3 0
3 years ago
Can you please help please please help me with this question please
Igoryamba

Answer:

9.99

Step-by-step explanation:

7 0
3 years ago
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