The answer will be 53/135, or in decimal form, 0.39259259...
To get 10% of your calories from polyunsaturated fats you would need to eat 200 calories worth. So 1 serving of walnuts would give you 180 calories. So one serving of walnuts would be 9% of your daily calories.
Answer: 7 pigeons sitting on the branches, 5 pigeons under the tree
=12 in total
Step-by-step explanation:
Upper branch has x pigeons, lower has y.
Top branch said: "If one of you flies up to us our number will be double yours":
Well, if one of the bottom branch flies up, the top branch will have x+1 birds and the bottom will have (y−1). The top will have double the bottom, so:
x+1=2(y−1)
Top branch said: "If one of us flies down to you, our numbers will be equal":
Now, the top branch will have x−1 and the bottom y+1. The numbers should be equal:
x−1=y+1
SOLUTION:
Step 1 :
In this question, we are told that a marketing research company needs to estimate the average total compensation of CEOs in the service industry.
We also have that: Data were randomly collected from 38 CEOs and the 98% confidence interval was calculated to be ($2,181,260, $5,836,180).
Then, we are asked to find the margin error for the confidence interval.
Step 2:
We need to recall that:
![\text{Higher Confidence Interval, CI}_{H\text{ = }}X\text{ + }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BHigher%20Confidence%20Interval%2C%20CI%7D_%7BH%5Ctext%7B%20%3D%20%7D%7DX%5Ctext%7B%20%2B%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
![\text{Lower Confidence Interval , CI}_{L\text{ }}=\text{ X - }\frac{Z\sigma}{\sqrt[]{n}}](https://tex.z-dn.net/?f=%5Ctext%7BLower%20Confidence%20Interval%20%2C%20CI%7D_%7BL%5Ctext%7B%20%7D%7D%3D%5Ctext%7B%20X%20-%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%7D)
It means that:
![\text{Margin of error, }\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{CI_{H\text{ - }}CI_L}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%20%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7BCI_%7BH%5Ctext%7B%20-%20%7D%7DCI_L%7D%7B2%7D)
where,
putting the values into the equation for the margin of error, we have that:
![\text{Margin of error,}\frac{Z\sigma}{\sqrt[]{n}\text{ }}\text{ = }\frac{5,836,180\text{ - }2,181,260\text{ }}{2}](https://tex.z-dn.net/?f=%5Ctext%7BMargin%20of%20error%2C%7D%5Cfrac%7BZ%5Csigma%7D%7B%5Csqrt%5B%5D%7Bn%7D%5Ctext%7B%20%7D%7D%5Ctext%7B%20%3D%20%7D%5Cfrac%7B5%2C836%2C180%5Ctext%7B%20%20-%20%7D2%2C181%2C260%5Ctext%7B%20%7D%7D%7B2%7D)
CONCLUSION:
The margin error for the confidence interval is 1, 827, 460
