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3 years ago

14

Select all the values that are equivalent to 9 pennies 1: model of 9 hundredths 2: 90/100 3: model of 9/10 4: 9/100 5: 9/10 6: $

0.09

1 answer:

DochEvi [55]3 years ago

4 0

The correct answers are 1,4,6

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I forgot how to do smh. please help

Mazyrski [523]

$\bf ~\hspace{7em}\textit{negative exponents}
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a^{-n} \implies \cfrac{1}{a^n}
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a^n\implies \cfrac{1}{a^{-n}}
~\hspace{4.5em}
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\cfrac{y^3z^5}{y^4z}\implies \cfrac{y^3z^5}{y^4z^1}\implies \cfrac{z^5\cdot z^{-1}}{y^{-3}y^4}\implies \cfrac{z^{5-1}}{y^{-3+4}}\implies \cfrac{z^4}{y}$

4 0

3 years ago

Will give brainiest!!!

azamat

Answer:

i take bite :3

Step-by-step explanation:

6 0

3 years ago

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Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find the area of the region between the curve y= 2ln(x) and the horizontal axis for 1<= x <= 4

marissa [1.9K]

Answer:

5.09 units

Step-by-step explanation:

Given equation

$y=2\ln x=f(x)$ in the interval $1\le x\le 4$

So we integrate $y$ in the given interaval

$\int f(x)=2\int\limits^4_1 {\ln x}dx$

Let us integrate $\ln x$ first.

let

$u=\ln x, dv=dx$

$du=\dfrac{1}{x}, v=x$

$\int\ln x dx=udv$

Using integration by parts we get

$uv-\int vdu$

$=x\ln x-\int x\dfrac{1}{x}dx$

$=x\ln x-dx$

$=x\ln x-x+C$

So here

$\int f(x)=2\int\limits^4_1 {\ln x}dx\\ =2(x\ln x-x)_1^4\\ =2[(4\ln 4-4)-(1\ln 1-1)]\\ =2[4\ln 4-4+1]\\ =5.09\ units$

The area of the the region between the curve and horizontal axis is 5.09 units.

5 0

3 years ago

Your friend claims that the only solution to the trigonometric equation tan B = square root of 3 is B = 60 degrees. Is your frie

dolphi86 [110]

Answer:

Yes, Friend is correct.

Step-by-step explanation:

Given:

Tan B = √3

Find:

Value of B

Computation:

Tan B = √3

Tan B = Tan 60°

By comparing

B = 60°

Yes, Friend is correct.

3 0

3 years ago